I want to write two variable to a file using Python.
Based on what is stated in this post I wrote:
f.open('out','w')
f.write("%s %s\n" %str(int("0xFF",16)) %str(int("0xAA",16))
But I get this error:
Traceback (most recent call last):
File "process-python", line 8, in <module>
o.write("%s %s\n" %str(int("0xFF", 16)) %str(int("0xAA", 16)))
TypeError: not enough arguments for format string
You are not passing enough values to %, you have two specifiers in your format string so it expects a tuple of length 2. Try this:
f.write("%s %s\n" % (int("0xFF" ,16), int("0xAA", 16)))
Better use format this way:
'{0} {1}\n'.format(int("0xFF",16), int("0xAA",16))
Also there is no need to wrap int with str.
Firstly, your opening the file is wrong f.open('out', 'w') should probably be:
f = open('out', 'w')
Then, for such simple formatting, you can use print, for Python 2.x, as:
print >> f, int('0xff', 16), int('0xaa', 16)
Or, for Python 3.x:
print(int('0xff', 16), int('0xaa', 16), file=f)
Otherwise, use .format:
f.write('{} {}'.format(int('0xff', 16), int('0xaa', 16)))
The % operator takes an object or tuple. So the correct way to write this is:
f.write("%s %s\n" % (int("0xFF", 16), int("0xAA",16)))
There are also many other ways how to format a string, documentation is your friend http://docs.python.org/2/library/string.html
You need to supply a tuple:
f.open('out','w')
f.write("%d %d\n" % (int("0xFF",16), int("0xAA",16)))
"%s %s\n" % (str(int("0xFF", 16)), str(int("0xAA", 16)))str(int()), anyway?"%i %i\n" % (int("0xFF", 16), int("0xAA",16))would work just as well and, in my opinion, is a bit clearer. Also, if only hexadecimal strings are guaranteed to begin with0xthen you can useint(string, 0), as that will automatically convert properly-prefixed octal strings and handle decimal strings correctly as well. If all your strings are hex and might not be preceded by0xthen usingint(string, 16)is probably how you need to go, though.