passing multiple arguments to function php

Question

Apologies for the newbie question but i have a function that takes two parameters one is an array one is a variable function createList($array, $var) {}. I have another function which calls createList with only one parameter, the $var, doSomething($var); it does not contain a local copy of the array. How can I just pass in one parameter to a function which expects two in PHP?

attempt at solution :

function createList (array $args = array()) {
    //how do i define the array without iterating through it?
 $args += $array; 
 $args += $var;


}

Petruza · Accepted Answer · 2014-11-21 14:35:52Z

60

If you can get your hands on PHP 5.6+, there's a new syntax for variable arguments: the ellipsis keyword.
It simply converts all the arguments to an array.

function sum(...$numbers) {
    $acc = 0;
    foreach ($numbers as $n) {
        $acc += $n;
    }
    return $acc;
}
echo sum(1, 2, 3, 4);

Doc: ... in PHP 5.6+

answered Nov 21, 2014 at 14:35

Petruza

12.4k26 gold badges91 silver badges146 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

sjagr Over a year ago

It's also worth noting that this is advantageous because you can now type hint a variable number of arguments, as the accepted answer mentions that is a huge downside of func_get_args()

eyered · Accepted Answer · 2014-12-17 20:35:06Z

22

You have a couple of options here.

First is to use optional parameters.

  function myFunction($needThis, $needThisToo, $optional=null) {
    /** do something cool **/
  }

The other way is just to avoid naming any parameters (this method is not preferred because editors can't hint at anything and there is no documentation in the method signature).

 function myFunction() {
      $args = func_get_args();

      /** now you can access these as $args[0], $args[1] **/
 }

edited Dec 17, 2014 at 20:35

eyered

1171 silver badge8 bronze badges

answered May 29, 2013 at 21:00

Orangepill

24.7k3 gold badges44 silver badges64 bronze badges

1 Comment

Undermine2k Over a year ago

Awesome did not know you can set a parameter to null thanks!

crush · Accepted Answer · 2013-05-29 20:59:48Z

4

You can specify no parameters in your function declaration, then use PHP's func_get_arg or func_get_args to get the arguments.

function createList() {
   $arg1 = func_get_arg(0);
   //Do some type checking to see which argument it is.
   //check if there is another argument with func_num_args.
   //Do something with the second arg.
}

answered May 29, 2013 at 20:59

crush

17.1k10 gold badges65 silver badges104 bronze badges

Collectives™ on Stack Overflow

passing multiple arguments to function php

attempt at solution :

3 Answers 3

1 Comment

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

attempt at solution :

3 Answers 3

1 Comment

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related