String.split issue in listView

Question

I'm trying to read the contents of a text file into a list view. The text file is in the format

Item 1
Subitem1 | Subitem2 | Subitem3

Item 2 
Subitem1 | Subitem 2 | Subitem3

Item 3
Subitem1 | Subitem2 | Subitem3

This is the logic I used. Search file for specific item

  while(scanner.hasNextLine())
  {    
     line=scanner.next line();
     if(query.equals(line))
     line = scanner.next line();
  }
  return line;

Take the returned line value and split it into String []

  String[] myArray = returnedLine.split("|");

Convert this into List for the list view

  List<String> disp = new ArrayList<String>();
  disp = Arrays.as list(myArray);

The code works. However, the contents of the list view looks weird, with each alphabet in a new listView row. S on one row, u one the next, followed by b, I, t, e, m and 1. All on separate rows

Also, I just checked. Whatever the query string is, the return value is always the last line of the file ie, subitema of item 3 — user2424211
– user2424211, Commented May 29, 2013 at 21:26
@DevOfZot's answer looks good to me and I think this second problem is because you probably want to do a break; instead of the second line = scanner.nextLine(); in your while loop. — HexAndBugs
– HexAndBugs, Commented May 29, 2013 at 21:28
I'll have to add the break after scanner.nextLine(); since I want the return to be the line AFTER the item — user2424211
– user2424211, Commented May 29, 2013 at 21:32
Are you sure that's what you want to do? Don't you just want to exit when you've found the line that matches query? Without all your code it's difficult to be sure what you're doing, but in any case your existing code risks a NoSuchElementException as you're calling scanner.nextLine() without checking scanner.hasNextLine() for the second call to scanner.nextLine() — HexAndBugs
– HexAndBugs, Commented May 29, 2013 at 21:38

DevOfZot · Accepted Answer · 2013-05-29 21:37:28Z

3

The String.split() function takes a regular expression, not a character, and pipe is a special character in regex. Try this:

String[] myArray = returnedLine.split("\\|");

edit: as flightplanner pointer out, your while should probably look like this:

while(scanner.hasNextLine())
{    
    line=scanner.next line();
    if(query.equals(line)) {
        line=scanner.next line();
        break;
    }
}

edited May 29, 2013 at 21:37

answered May 29, 2013 at 21:23

DevOfZot

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3 Comments

user2424211 Over a year ago

And what about the other issue? It always returns the last line of the file

DevOfZot Over a year ago

See flightplanner's comment. You probably only want to call scanner.nextLine() once in the while() statement.

user2424211 Over a year ago

Basically, the string query will be, for example, item 1. When it finds it, it should read the next line @DevOfZot

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