How would I go about splitting a String in several places where ever a certain character occurs.
For example, here is the String
"10067829311288"
When looping through the String, if the digit is a "1", it will take the next the next two characters and split, if not, it will take only one. Here's how it should be split.
100 67 82 93 112 88
Any help is appreciated.
How about something like this:
public static void main(String[] args) {
final String s = "10067829311288";
final List<Integer> split = new LinkedList<>();
int i = 0;
while (i < s.length()) {
final char c = s.charAt(i);
final int remain = s.length() - i;
final int step;
if (c == '1') {
step = Math.min(remain, 3);
} else {
step = Math.min(remain, 2);
}
split.add(Integer.parseInt(s.substring(i, i + step)));
i += step;
}
System.out.println(split);
}
Or, with regex:
public static void main(String[] args) {
final String s = "10067829311288";
final List<Integer> split = new LinkedList<>();
final Pattern pattern = Pattern.compile("1?\\d{2}");
final Matcher matcher = pattern.matcher(s);
while (matcher.find()) {
split.add(Integer.parseInt(matcher.group()));
}
System.out.println(split);
}
1?\\d{2} matches an optional 1 greedily followed by two digits. So if there isn't a 1 it will grab two digits, if there is a one it will grab that and two more digits.Here is one possible solution.
public void split() {
System.out.println(split("10067829311288"));
}
public List<String> split(String text) {
List<String> result = new LinkedList<>();
Matcher m = Pattern.compile("1?\\d\\d").matcher(text);
while (m.find()) {
result.add(m.group());
}
return result;
}
Update: simplified my regex after seeing how Boris the Spider did his regex.
You can try this way
"10067829311288".split("(?<=\\G(1\\d\\d|[02-9]\\d))");
demo
System.out.println(Arrays.toString("10067829311288".split("(?<=\\G(1\\d\\d|[02-9]\\d))")));
output: [100, 67, 82, 93, 112, 88]
\\G represents position of last match (split) and if first match doesn't exists it represents start of the String.
(?<=regex) is look-behind mechanism
\\d represents digit
| is OR
112instead of1128?