Removing substring from string using Regex javascript

Question

I have a string in javascript like this:

frmSearch=FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=22.234567:Paid=

I want to remove :FeeAmount=22.234567 part from this string using Regex or string.replace.

It can be empty like this:

frmSearch=FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=:Paid=

or it can contain any value

I tried this:

var str= frmSearch.substr(frmSearch.indexOf(":FeeAmount"), frmSearch.indexOf(":Paid="));

How can I do it using regex?

I have been trying substring and string.replace combination but they don't work — DotnetSparrow
– DotnetSparrow, Commented Jun 2, 2013 at 8:13
@DotnetSparrow: Show the effort, so people can help you figure out where you went wrong (and so this doesn't look like a "please write this for me" question). — T.J. Crowder
– T.J. Crowder, Commented Jun 2, 2013 at 8:14
@T.J.Crowder - It should've worked with .substring() or .slice(), both of which take a start and end index, but .substr() takes a start and length. DotnetSparrow - is your desired output the original string minus that part (as assumed by the answers jcsanyi and I posted), or is the FeeAmount=... the part you want to keep? — nnnnnn
– nnnnnn, Commented Jun 2, 2013 at 9:50

nnnnnn · Accepted Answer · 2013-06-02 08:14:44Z

4

var frmSearch = "FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=22.234567:Paid=";
frmSearch = frmSearch.replace(/(^|:)FeeAmount=[^:]*/,'$1FeeAmount=');

...will leave FeeAmount= in the string. To remove it completely:

frmSearch = frmSearch.replace(/(^|:)FeeAmount=[^:]*/,'');

answered Jun 2, 2013 at 8:14

nnnnnn

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9 Comments

jcsanyi Over a year ago

My understanding is that the second example in the question is a second possible input, not the expected output.

DotnetSparrow Over a year ago

@nnnnn what does it mean by (^|:) and [^:]* ?

nnnnnn Over a year ago

There's plenty of JS regex documentation available.

T.J. Crowder Over a year ago

@DotnetSparrow: (^|:)FeeAmount = Match FeeAmount at the beginning of the string (^), or after a :. The [^:]* means "zero or more characters that are NOT :".

nnnnnn Over a year ago

@jcsanyi - Yes. It wasn't a problem when I thought the idea was to leave an "empty" FeeAmount= in the string, but I don't have time now to fix the second version. (I'm off to cook dinner.)

|

jcsanyi · Accepted Answer · 2013-06-02 08:14:36Z

2

How about this?

var input = 'frmSearch=FeeType=RecordingSpend:LoginID=:PersonCalled=:FeeAmount=22.234567:Paid=';
var output = input.replace(/:FeeAmount=[0-9.]*/, '');

answered Jun 2, 2013 at 8:14

jcsanyi

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Comments

JNF · Accepted Answer · 2013-06-02 08:14:46Z

0

According to the question, the matching regex rule may be

':FeeAmount=[^:]*'

answered Jun 2, 2013 at 8:14

JNF

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