PHP require/include file

Question

I have the following program Structure:

Root directory：-----index.php
                       |-------TPL directory
                                 |-------------header.php
                                 |-------------index.php
                                 |-------------footer.php
php file loading structure:

Root directory:index.php ----require/include--->tpl:index.php
                                                      |----require/include-->header.php
                                                      |----require/include-->footer.php

Root index.php :

    <?php
function get_header(){
    require('./tpl/header.php');
}

function get_footer(){
    require('./tpl/footer.php');
}

$a = "I am a variable";

require('./tpl/index.php');

TPL:index.php:

    <?php
get_header();//when I change require('./tpl/header.php'); variable $a can work!!
echo '<br />';
echo 'I am tpl index.php';
echo $a;
echo '<br />';
get_footer();//when I change require('./tpl/footer.php'); variable $a can work!!

TPL:header.php:

    <?php
echo 'I am header.php';
echo $a;//can not echo $a variable
echo '<br/>';

TPL:footer.php:

    <?php
echo '<br />';
echo $a;//can not echo $a variable
echo 'I am footer';

For some reason when I used function to require header.php and footer.php my variable $a doesn't get echoed. It works fine if I use header.php or footer.php on its own. I do not understand what the problem is. What do you think is the issue here?

ɴᴀᴛᴇ ᴅᴇᴠ · Accepted Answer · 2013-06-02 14:47:26Z

4

Your issue is probably just scope of a function does not automatically include global variables. Try setting $a to global like global $a;, example below for your get_header() function:

function get_header(){
    global $a; // Sets $a to global scope
    require('./tpl/header.php');
}

answered Jun 2, 2013 at 14:47

ɴᴀᴛᴇ ᴅᴇᴠ

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1 Comment

user2427932 Over a year ago

3Q!It now appears that only use global.

luk2302 · Accepted Answer · 2013-06-02 14:48:15Z

1

Using the include inside a function includes the code directly in that function. Therefore the variable is a locally in that function accessable variable - it is not set outside the function.

If you require/include without a function $a becomes a global variable.

answered Jun 2, 2013 at 14:48

luk2302

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Comments

Oussaki · Accepted Answer · 2013-06-02 14:55:53Z

0

make your variable As Global

global $YourVar;

answered Jun 2, 2013 at 14:55

Oussaki

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