JavaScript: If statement on Array declaration

Question

Is it possible to put an if statement within an Array Declaration?

Code:

dayOfWeek = [if($('#sunday').checked()){$('#sunday').val()}];

Browser error: Uncaught SyntaxError: Unexpected token if.

I tried too:

$('#domingo').checked() ! $('#domingo').val() : 0

Browser error: Uncaught SyntaxError: Unexpected token !

EDIT

As @bažmegakapa answered the code that works with no error is:

diasSemana = new Array($domi.is(':checked') ? $domi.val() : null, $lun.is(':checked') ? $lun.val() : null);

This did not work:

$('#domingo').checked() ? $('#domingo').val() : 0

Browser showed this error: Uncaught TypeError: Object [object Object] has no method 'checked'

Regards!

Use [] instead of new Array().

kapa
– kapa

2013-06-03 19:05:50 +00:00
Commented Jun 3, 2013 at 19:05 — kapa
– kapa, Commented Jun 3, 2013 at 19:05

kapa · Accepted Answer · 2013-06-03 17:16:10Z

4

What you need is called the ternary or conditional operator:

$('#domingo').checked() ? $('#domingo').val() : 0

However, it is not a good idea to query the DOM twice for the same element. Save the resulting jQuery object into a variable beforehand and reuse it:

var $domi = $('#domingo');
dayOfWeek = [$domi.checked() ? $domi.val() : 0];

I don't know what .checked() is, maybe you meant .is(':checked').

Some fiddle demo to play with

edited Jun 3, 2013 at 17:16

answered Jun 3, 2013 at 17:10

kapa

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2 Comments

Daniel Over a year ago

great answer! The first approach showed me an error but second worked fine. Regards

kapa Over a year ago

@eyyo Yep, the error is due to the .checked() function which does not exist :).

Ben Reich · Accepted Answer · 2013-06-03 17:11:06Z

4

Try using the javascript ternary operator, documented here:

$('#domingo').checked() ? $('#domingo').val() : 0

answered Jun 3, 2013 at 17:11

Ben Reich

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1 Comment

Daniel Over a year ago

This code is showing me this error: Uncaught TypeError: Object [object Object] has no method 'checked'. Thanks anyway

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