single value getJSON from php to into a JavaScript variable

Question

I need to create a JavaScript variable to compare to another variable.

One of those variables comes from a php file. So i created a simple php array and used json_encode($array) to convert it to json.
Using ajax/getJSON, how do I grab that value, put it in a variable, and use it for logical testing?

I've been seeing some examples of getJSON but they are all complex arrays where mine is just a single value. Thanks

What does the JSON data look like that you are returning?

crush
– crush

2013-06-03 17:31:00 +00:00
Commented Jun 3, 2013 at 17:31 — crush
– crush, Commented Jun 3, 2013 at 17:31
use success callback function of $.getJSON method

A. Wolff
– A. Wolff

2013-06-03 17:31:58 +00:00
Commented Jun 3, 2013 at 17:31 — A. Wolff
– A. Wolff, Commented Jun 3, 2013 at 17:31
{"0":"abc123","CLIENT":"abc123"}

Gio
– Gio

2013-06-03 17:32:14 +00:00
Commented Jun 3, 2013 at 17:32 — Gio
– Gio, Commented Jun 3, 2013 at 17:32

Spokey · Accepted Answer · 2013-06-03 17:31:32Z

2

$.getJSON('yoururl.php', function(json_data){
   var compare_me = json_data.key // key is the name of the json key name
});

answered Jun 3, 2013 at 17:31

Spokey

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3 Comments

Gio Over a year ago

thanks. I added alert(compare_me); and i got an alert box with "undefined"

Spokey Over a year ago

@Gio did you add var compare = json_data.CLIENT; ?

Gio Over a year ago

Nope... I'm well versed in php/html/css/sql, etc but I'm in the beginning stages of JavaScript and jQuery. Your suggestion worked.. thanks!

Gonzalo De-Spirito · Accepted Answer · 2013-06-03 17:38:53Z

0

$.post('url_of_oyu_file.php', function(responseText){
   var json_var = JSON.parse(responseText); //Convert the string into object.
   if(json_var.val = value_to_compare){
     //Do Stuff...
   }
});

answered Jun 3, 2013 at 17:38

Gonzalo De-Spirito

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Comments

Mahesh · Accepted Answer · 2013-06-03 17:52:04Z

0

PHP

your-file.php

<?php
 echo json_encode(array('value' => 1));
 exit;
?>

Try this

$.get('your-file.php', function(data){
 if (data.value === value_to_compare) {
   // Do stuff
 }
}, 'json');

edited Jun 3, 2013 at 17:52

answered Jun 3, 2013 at 17:46

Mahesh

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