How to Call a function that execute on a DIV using PHP function?

Question

This my code :

<?php
    if (isset($_GET["add"]))
    {
?>

<script type="text/javascript" language="javascript">
    var i=0;

    function createDiv()
    {
        $('#newdiv').append('<div id="div"'+i+'" class="ex" style="text-align: left;">Life Really suck</div>');

       i++;

       $( ".ex" ).draggable({containment:'parent',cursor:'pointer',opacity:0.6});
       $( ".ex" ).droppable();

    }

    createDiv(); // will execute when it loads this line
</script>

<?php
    }   
?>

<div id = "newdiv">    </div>

How can I make the function execute in the DIV outside of the condition statement?

I need the function execute normally is the GET["add"] is set

Now I it does not execute in the DIV even though the function does run

Can you please edit your message to correct typo and make it more clear ? I don't understand the problem nor what you want to do — Asenar
– Asenar, Commented Jun 4, 2013 at 8:09
It's Normal,You want to Append a content on a div, but your div don't exist, Create your div in Javascript, or, before your function. — Doc Roms
– Doc Roms, Commented Jun 4, 2013 at 8:21
I want to create it outside of the condition statement, is it possible? — user2399158
– user2399158, Commented Jun 4, 2013 at 8:26
Yes, Just Place your '<div id="newdiv"></div>' before your Php code in your page. ( and read other answer, your Jquery function isn't correct ^^ ) — Doc Roms
– Doc Roms, Commented Jun 4, 2013 at 8:28

Asenar · Accepted Answer · 2013-06-04 08:22:46Z

2

surround your createDiv() call by $(document).ready(function(){ and }), this will execute what's inside only after the page is fully loaded.

answered Jun 4, 2013 at 8:22

Asenar

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