php for loop from array stops after 3 loops

Question

I have an array that looks like this.

Array (
    [0] => Array (
        [0] => MDT 2920 P
        [1] => MDT 1210 P
        [2] => MDT 939 P
        [3] => MDT 1760 P
        [4] => PDT 23800 P
    )
    [1] => Array (
        [0] => MDT
        [1] => MDT
        [2] => MDT
        [3] => MDT
        [4] => PDT
    )
    [2] => Array (
        [0] => 2920
        [1] => 1210
        [2] => 939
        [3] => 1760
        [4] => 23800
    )
)

I want to loop through array in the first key of [2] and echo all the values.

for ($i = 0; $i < count($nt); $i++)
{
    echo $nt[2][$i];
    echo "<br />";
}

this works, but stops after three loops and the output looks like this:

2920
1210
939

I am expecting -- hoping for this:

I don't understand why it is stopping. thanks.

Filippos Karapetis · Accepted Answer · 2013-06-04 23:00:16Z

6

Your problem lies here:

for($i = 0; $i < count($nt); $i++)

You are counting the elements of $nt (which are 3), but you want to access the elements of $nt[2] (which are 5). Thus, you need to change the above line to:

for($i = 0; $i < count($nt[2]); $i++)

answered Jun 4, 2013 at 23:00

Filippos Karapetis

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Comments

Danijel · Accepted Answer · 2013-06-04 23:04:09Z

2

Try to use foreach loop:

   foreach ( $array[2] as $value ) {
        echo $value;
        echo "<br />";
    }

answered Jun 4, 2013 at 23:04

Danijel

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Comments

exussum · Accepted Answer · 2013-06-04 23:00:18Z

1

for($i = 0; $i < count($nt); $i++)

is the cuplrit

you should be using

for($i = 0; $i < count($nt[2]); $i++)

answered Jun 4, 2013 at 23:00

exussum

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Comments

Luka Kerr · Accepted Answer · 2016-10-29 08:15:48Z

1

$number=array(1,2,3,4,5);

foreach($number as $n)
{   
echo "value is $n <br>";
}

edited Oct 29, 2016 at 8:15

Luka Kerr

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answered Oct 29, 2016 at 7:59

Mehul Jariwala

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1 Comment

andreas Over a year ago

While this code snippet may solve the question, including an explanation really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion.

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