How to add XML Content to form in Symfony

Question

I don't find a way to add "button" or "input" fields to a form to the crawler in Symfony for testing. I'm doing this :

$crawler = $this->client->request('GET', '');
$document = new \DOMDocument();
$document->loadXml('<button type="submit" name="_submit" href="#">Create</button >');
$nodeList = $document->getElementsByTagName('button');
$node = $document->getElementsByTagName('button')->item(0);
$crawler->addNode($node, $form);
var_dump($crawler->filter('button[name="_submit"]')->text()); //Return Create Logic

But when i try to send my form i've got :

$form = $crawler->selectButton('_submit')->form(array(
                                                'login-input' => 'XXXXXX',
                                                'pass-input'  => 'XXXXX',
                                            ));

This doesn't work i've got :

LogicException: The selected node does not have a form ancestor.

I don't have any button or input fields because it's a javascript submit.
Someone have any idea ?

EDIT

I've found an another way: I send directly ajax request, and i've got the same effect @redbirdo, your solution doesn't work for me, and isn't what i want at the start of my question

redbirdo · Accepted Answer · 2013-06-05 13:22:10Z

1

You can simulate a POST request in a test using the client like this:

$client->request(
    'POST',
    '/submit',
    array('name' => 'Fabien'),
    array('photo' => $photo)
);

There are more examples under Working with the Test Client in the Testing section of the Symfony manual.

EDIT:

The second parameter should be the relative or absolute url of the page being tested. The '/submit' here is just a symfony example.

edited Jun 5, 2013 at 13:22

answered Jun 5, 2013 at 9:20

redbirdo

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1 Comment

Babou34090 Over a year ago

I've tried this : '$this->client->request('POST', '/submit', array('login-input' => 'XXXXX', 'pass-input' => 'XxXX'));' but doesn't work, i've got an 404 error page

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