2

I need to port some JS code which involves Math.random()*2147483648)^(new Date).getTime(). While it looks like for smaller numbers, the python function and the JS function are equivalent in function, but with large numbers like this, the values end up entirely different.

Python:

>>> 2147483647 ^ 1257628307380
1257075044427

Javascript:

> 2147483647 ^ 1257628307380
-1350373301

How can I get the Javascript value from python?

2 Answers 2

8

Python has unlimited-precision integers, while Javascript is using a 32-bit integer. You can manually apply a 32-bit limit to get the result you want:

def xor32bit(a, b):
    m = (a ^ b) % (2**32)
    if m > (2**16):
        m -= 2**32
    return m
Sign up to request clarification or add additional context in comments.

4 Comments

Better use 1 << 32 or directly 4294967296 instead of 2**32.
Using 4294967296 would be silly—it kills readability. 2**32 is not absurdly expensive and it probably constant-folded. 1<<32 makes easily as much sense.
I just checked, and Python 3.1 constant-folds 2**16 and 2**32.
Yes, it seems this was introduced in Python 2.5. 2.3 and 2.4 compute the value in bytecode, but 2.5 computes it in the compiler and the bytecode simply loads the constant value.
4

Easiest way would be to use ctypes to get the same overflow behavior as Javascript:

>>> import ctypes
>>> ctypes.c_int(1257075044427)
c_long(-1350373301)

To get the value:

>>> ctypes.c_int(1257075044427).value
-1350373301

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.