I am a newbie in Fortran. Can any1 tell me how to define an integer array in prior. E.g. I want to define an array with no.of days in 12 months. like...
integer,allocatable(12,1) :: days
days=[31,28,31,30,31,30,31,31,30,31,30,31]
Is this syntax correct? If not, please let me know the correct one.
Thanks Praveen
If you want a dynamically allocated array, try the following:
program arraytest
implicit none
integer, allocatable :: a(:)
allocate(a(12))
a = (/31,28,31,30,31,30,31,31,30,31,30,31/)
print *, a
end program arraytest
integer, dimension(12) :: a = (/ 31, 28, 31, 30, ... /)
for "static" array. the [ ] instead of (/ /) is correct for Fortran 2003 and later; all the compilers I know allow that syntax even though they do not implement fully F2003. For dynamic array:
integer, dimension(:) :: a ! ... allocate(a(12)) a = (/ .... /) ! ... deallocate(a)
is an option too.
In FORTRAN 77, I'd say
INTEGER DAYS(12) / 31,28,31,30,31,30,31,31,30,31,30,31 /
That's declaration and initialization in one.
If you want, you can also separate the two:
INTEGER DAYS(12)
DATA DAYS / 31,28,31,30,31,30,31,31,30,31,30,31 /
Probably doesn't need to be allocatable, does it, since it's just a constant array:
INTEGER :: a(12) = (/ 31,28,31,30,31,30,31,31,30,31,30,31 /)
