Java Convert this string to JSONArray [closed]

Question

I am getting the following String response from a server:

{"fid":"1272","uri":"http://someurl/services/file/1272"}

I need to convert it into a JSONArray. Any help?

By the way, I tried this and it does not work:

String response=getResponseFromServer();
JSONArray array = new JSONArray(response);

I get the error:

org.json.JSONException: Value {"fid":"1272","uri":"http://someurl/services/file/1272"} of type org.json.JSONObject cannot be converted to JSONArray

It is a Java String, not a JSON object yet. He's doing Java, not Javascript. — marlenunez
– marlenunez, Commented Jun 9, 2013 at 17:40

keelar · Accepted Answer · 2013-06-09 17:33:40Z

12

If you're talking about using the JSON in java library, then since your input string is a JSON object, not a JSON array, you should first load it using JSONObject:

String response=getResponseFromServer();
JSONObject jsonObject = new JSONObject(response);

After that, you can use toJSONArray() to convert a JSONObject to JSONArray given an array of key strings:

String[] names = JSONObject.getNames(jsonObject);
JSONArray jsonArray = jsonObject.toJSONArray(new JSONArray(names));

edited Jun 9, 2013 at 17:33

answered Jun 9, 2013 at 17:26

keelar

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2 Comments

Inf Min Over a year ago

Ok. Thanks. JSONObject was new to me.

keelar Over a year ago

No problem, you're welcome. That's what stackoverflow for :)

Community · Accepted Answer · 2017-05-23 11:53:01Z

5

If you do a search right here on StackOverflow for Java String to JSONArray, you should get this answer: Converting from JSONArray to String then back again

JSONArray jArray;
String s = jArray.toString(); // basically what you have ;)
JSONArray newJArray = new JSONArray(s);

edited May 23, 2017 at 11:53

CommunityBot

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answered Jun 9, 2013 at 17:25

marlenunez

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3 Comments

Inf Min Over a year ago

The string I have is not in the format that the JSONArray constructor accepts.

marlenunez Over a year ago

Ok, so see @keelar's answer in that case.

Alexey Ivanov Over a year ago

The OP does not have JSONArray yet, and the JSON string in the question represents a JSONObject rather than a JSONArray.

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