I have a two variable one is string contains number and another one is number, I want increase the numeric part of string upto second number.
$n ='sh500';
$c = 3;
for($i=$n;$i<$c;$i++)
echo $i.'<br>';
I want output like:
sh500
sh501
sh502
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7 Answers
Use $n++ where $n = 'sh500'. It works.
$n ='sh500';
$c = 3;
for($i = 0;$i < $c;$i++) {
echo $n++.'<br>';
}
Will output
sh500 <br>
sh501 <br>
sh502 <br>
It even works when ending with a alphanumeric character, because php converts it to the ASCII value of the character and adds one so a will become b and so on. But that's out of the scope of the question :)
Comments
$x="sh500";
$x = substr($x,0,2) . (substr($x,2) + 1);
echo $x;
echoes sh501 (works for any string having a number from 3rd character)
Comments
$n = 'sh';
for($i = 500; $i < 503; $i++) {
echo "$n$i\n";
}
3 Comments
Rajendra Yadav
$n ='sh500'; is not fixed,it change dynamicaly like $n ='dewd94' or $n='rew231' etc.
Pritesh Tayade
then place this code in function and just pass the dynamic number to the function and use it to initialize
$i (can also pass the upper limit then)
mzedeler
@er_Rajendraa: then you can start out by splitting the text from the numeric part using
preg_match.$n="sh50";
for($i=0;$i<10;$i++){
$j=$n.$i;
echo $j."<br>";
}
it echo: sh500 sh501 sh502 sh503 sh504 sh505 sh506 sh507 sh508 sh509
Comments
if it is always a string of length 2 else use preg_match to find the first occurrence of a number. http://www.php.net/manual/en/function.preg-match.php
$number = intval(substr($n, 2));
$number++;
echo substr($n, 0, 2) . $number;
Comments
$x = "sh500";
$s = substr($x, 0, 2);
$n = substr($x, 2);
$c = 3;
for ($i = $n; $i < ($n + $c); $i++)
{
echo $s.$i.'<br>';
}
OR another simple way is...
$n ='sh500';
$c = 3;
for ($i = 0; $i < $c; $i++) {
echo $n++."<br>";
}
Output
sh500
sh501
sh502
