The string is setup like so:
href="PART I WANT TO EXTRACT">[link]
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What shell are you talking about?Pekka– Pekka2009-11-09 22:11:29 +00:00Commented Nov 9, 2009 at 22:11
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4 Answers
use awk
$ echo "href="PART I WANT TO EXTRACT">[link]" | awk -F""" '{print $2}'
PART I WANT TO EXTRACT
Or using shell itself
$ a="href="PART I WANT TO EXTRACT">[link]"
$ a=${a//"/}
$ echo ${a/&*/}
PART I WANT TO EXTRACT
Comments
Here's another way in Bash:
$ string="href="PART I WANT TO EXTRACT">[link]"
$ entity="""
$ string=${string#*${entity}*}
$ string=${string%*${entity}*}
$ echo $string
PART I WANT TO EXTRACT
This illustrates two features: Remove matching prefix/suffix pattern and the use of a variable to hold the pattern (you could use a literal instead).
answered Nov 10, 2009 at 1:11
Dennis Williamson
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expr "$string" : 'href="\(.*\)">\[link\]'
Comments
grep -o "PART I WANT TO EXTRACT" foo
Edit: "PART I WANT TO EXTRACT" can be a regex, i.e.:
grep -o http://[a-z/.]* foo
2 Comments
Josh
I'm using: >
grep -o 'http://[a-z/.A-Z0-9]*">\[link\]' but it's giving me: > http://img18.imageshack.us/img18/8079/69903601.jpg">[link] I don't want the stuff on the end.
ctd
Well, you could grep to find, and then use grep -o to just get the expression: >grep 'http://[a-z/.A-Z0-9]*">[link]' | grep -o 'http://[a-z/.A-Z0-9]*
