I have the following problem:
Let's say s = 'ab'. len(s) = 2. it has 2 indexes: 0 and 1. What I want to do is to make ab of length 1, or have an index of 0.
All help is welcome
Thanks
2 Answers
I think your question can be answered two ways:
>>> s = 'ab'
>>> s = s[:1]
>>> s
'a'
or you want string stored in collection
>>> s = 'ab'
>>> s = (s,)
>>> s[0]
'ab'
>>> s = 'ab'
>>> s = [s]
>>> s[0]
'ab'
Comments
If I understood your question then I guess you're looking for slicing:
>>> s = 'ab'
>>> s = s[:1]
>>> s
'a'
Update:
You need a list to do that.
>>> d ='abcefg'
>>> it = iter(d)
>>> d = [x + next(it) for x in it] #creates a list
>>> d
['ab', 'ce', 'fg']
>>> d[0]
'ab'
>>> d[1]
'ce'
>>> d[2]
'fg'
Another way using zip:
>>> d ='abcefg'
>>> it = iter(d)
>>> [x+y for x,y in zip(it,it)]
['ab', 'ce', 'fg']
answered Jun 13, 2013 at 7:10
Ashwini Chaudhary
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6 Comments
Isaac Altair
not quiet, for example d ='abcefg'. What I want is d[0] = 'ab', d[1] = 'ce', d[2] = [fg].
Ashwini Chaudhary
@IsaacAltair add such examples in your question, I've updated my solution.
Isaac Altair
We are not allowed to use lists in our assignment, but it is great to come to know various solutions. thanks = D
Ashwini Chaudhary
@IsaacAltair You can't do that with a string, in a string an index points to only a single character.
Ashwini Chaudhary
@IsaacAltair what is
print_board? This has nothing to do with your original question. |