Need to convert from XML to HTML in java

Question

Please give me suggestion as i need to convert from XML to HTML in java without using XSLT. As i was searching in the web but everywhere it was showing can convert from xml to html with use of only xslt/xsl?

Please guyz give me some suggestions?

i had one xml file which i need to convert and show into html page or in html format.As i dont have any xsl file for the same. — Uday Konduru
– Uday Konduru, Commented Jun 16, 2013 at 6:30
NFE answer below is the best solution for this simple usecase. Keep XML in original format and use a HTML page with javascript to parse and present it in the browser. — Mark O'Connor
– Mark O'Connor, Commented Jun 16, 2013 at 7:01
"..without using XSLT." Why 'without'? It is an excellent tool for the job. — Andrew Thompson
– Andrew Thompson, Commented Jun 16, 2013 at 9:25
@AndrewThompson---as i dont have any xsl and dont know how to write xsl for the same.And i dont have enough time to learn and write our own xsl.So i am trying and looking for different apporach — Uday Konduru
– Uday Konduru, Commented Jun 17, 2013 at 5:06

NFE · Accepted Answer · 2013-06-16 06:38:52Z

1

You can parse xml data using jQuery.parseXML and use data of it.

$.get('/url_of_the_xml_resource')
  .done(function(data){
    // parse the xml
    data = $.parseXML(data);
    //
    // do anything you want with the parsed data
  })
  .fail(function(){
    alert('something went wrong!');
  })
;

answered Jun 16, 2013 at 6:38

NFE

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acdcjunior · Accepted Answer · 2013-06-16 06:41:39Z

1

This will save root.xml's content as root.xml.html.

public static void main(String[] args) throws Exception {
    String xmlFile = "root.xml";
    Scanner scanner = new Scanner(new File(xmlFile)).useDelimiter("\\Z");
    String xmlContent = scanner.next();
    xmlContent = xmlContent.trim().replaceAll("<","&lt;").replaceAll(">","&gt;").replaceAll("\n", "<br />").replaceAll(" ", "&nbsp;");
    PrintWriter out = new PrintWriter(xmlFile+".html");
    out.println("<html><body>" + xmlContent + "</body></html>");
    scanner.close();
    out.close();
}

Note: This will retain the XML's original indentation and line breaking.

answered Jun 16, 2013 at 6:41

acdcjunior

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5 Comments

Uday Konduru Over a year ago

thanks for your input...let me try this also..but i want to know what do you mean by retain the XML's original indentation?

acdcjunior Over a year ago

In the xmlContent line, remove the .replaceAll("\n", "<br />").replaceAll(" ", " ") and the indentation will not be retained (then you'll see what I mean).

Uday Konduru Over a year ago

actually i want the xml content in some kind of sorting order in html page.But as per your suggestion i tried it was just outputing in html format

acdcjunior Over a year ago

You should update your questions with those additional requirements, then - we can't help you with that if we don't know you need it.

Uday Konduru Over a year ago

yes in the starting it was simple one only..but later scenario got changed..sorry for the same

Wai Ha Lee · Accepted Answer · 2017-04-12 12:12:30Z

-1

You can use StringEscapeUtils and use the method escapeHtml.

String yourXmlAsHtmlString = StringEscapeUtils.escapeHtml(yourXmlAsString);

edited Apr 12, 2017 at 12:12

Wai Ha Lee

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answered Apr 12, 2017 at 10:20

Amit Biton

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