I have string looking like this:
'Toy Story..(II) (1995)'
I want to split the line into two parts like this:
['Toy Story..(II)','1995']
How can I do it? Thanks.
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1Is that the only string you want to split? If not, could you give a few more examples?Lasse V. Karlsen– Lasse V. Karlsen2009-11-11 08:52:43 +00:00Commented Nov 11, 2009 at 8:52
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The reason I'm asking is that if that is the only string you want to split, I would just store it in its final form: l = ['Toy Story..(II)' '1995']Lasse V. Karlsen– Lasse V. Karlsen2009-11-11 08:54:28 +00:00Commented Nov 11, 2009 at 8:54
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1It will be difficult to automatically do the conversion from "Stroy" to "Story" for similar spelling errors, but apart from that, some simple string parsing or a simple regex will help.ndim– ndim2009-11-11 09:03:47 +00:00Commented Nov 11, 2009 at 9:03
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-1: The title is useless. Please change "what I want" to something that could be helpful to the thousands of people who look for help on this site every day.S.Lott– S.Lott2009-11-11 11:13:52 +00:00Commented Nov 11, 2009 at 11:13
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4 Answers
This code will get you started:
'Toy Stroy..(II) (1995)'.rstrip(')').rsplit('(',1)
Other than that, you can use r'\s*[(]\d{4}[)]\s*$' to match a four-digit number in parentheses at the end of the string. If you find it, you can chop it off:
s = ''
l = [s]
match = re.compile(r'\s*[(]\d+[)]\s*$').search(s)
if match is not None:
l = [s[:len(match.group(0))], s[-len(match.group(0)):].trim]
2 Comments
Charlie Epps
For your second method, I think it is not suitable for my problem. You see, if the sting is "Toy Stoy(1000) (1995)". the method won't work well. do you think so?
Aaron Digulla
Try it, it works since the regexp matches just one four-digit number at the end of the string.
One way is this:
s = 'Toy Stroy..(II) (1995)'
print s[:s.rfind('(')].strip()
print s[s.rfind('('):].strip("()")
Output:
Toy Stroy..(II)
1995
>>>
answered Nov 11, 2009 at 8:56
Nick Dandoulakis
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Comments
You could use regular expressions for that. See here: http://www.amk.ca/python/howto/regex/
Or you could use the split function and then manyally remove the parenthesis or other non desired characters. See here: http://www.python.org/doc/2.3/lib/module-string.html
2 Comments
Charlie Epps
The line may be complex, and It will be difficult to design a regular to work well.
Kaivosukeltaja
If the line always ends with the year, a simple regex with something like (.*)\s*((\d{4})) should do the trick. You'll have the name of the movie in the first backreference and the year in the second.
l[:-1].split("(")
1 Comment
Charlie Epps
Thanks, I'm sorry that I give a simple example. But in real word, the line would be like this "Toy Stoy..(II) (1995)". In this case, your method will not work well.