Regular expression to find "src" attribute of HTML "img" element in PHP [duplicate]

Question

I have a string, inside of that I have an image:

"<p><img src="http://yahoo.com/testfolder/userdata/editoruploadimages/confused man.jpg" /></p>"

I could not fetch the image URL with my regular expression. My code is:

preg_match_all("/src=([^\\s]+)/", $questArr_str, $images);

This code stops its execution when it encounters the space in the image name. It only returns "http://yahoo.com/testfolder/userdata/editoruploadimages/confused

The returned string should be: "http://yahoo.com/testfolder/userdata/editoruploadimages/confused man.jpg"

You are searching only for non whitespace characters in your regex, why should it match the space? Regex is not the best solution to match html, better to use a html/dom parser. — stema
– stema, Commented Jun 18, 2013 at 8:30

Beat · Accepted Answer · 2013-06-18 08:31:11Z

13

I'd catch everything inside the quotes:

preg_match_all('/src="([^"]+)"/', $questArr_str, $images);

answered Jun 18, 2013 at 8:31

Beat

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2 Comments

Oliver Dixon Over a year ago

Only matches the first pattern.

Beat Over a year ago

preg_match_all "searches subject for all matches" – you don't need the g flag

Adrian Thompson Phillips · Accepted Answer · 2013-06-18 08:30:26Z

8

The parts that reads ([^\s]+) means select anything that isn't a space.

Maybe try something like:

/src="([^"]+)"/

Which is select anything that isn't a double quote.

answered Jun 18, 2013 at 8:30

Adrian Thompson Phillips

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Comments

dot.Py · Accepted Answer · 2016-06-08 12:35:17Z

1

Thank every one for helping me out.

I found my solution by using:

pattern = "/src=([^\\\"]+)/"

edited Jun 8, 2016 at 12:35

dot.Py

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answered Jun 19, 2013 at 11:43

Santanu

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iKev61 · Accepted Answer · 2016-09-15 13:01:23Z

1

Here is an easy way to match <img /> tag src attribute and or it content in html/PHP with regular expression.

Sample:

<img class="img img-responsive" title="publisher.PNG" src="media/projectx/agent/author/post/2/image/publisher.PNG" alt="" width="80%" />

To match just src attribute content use

preg_match("%(?<=src=\")([^\"])+(png|jpg|gif)%i",$input,$result)

$result[0] will output media/projectx/agent/author/post/2/image/publisher.PNG

To match `src' attribute and it content use

preg_match("%src=\"([^\"])+(png|jpg|gif)\"%i",$input,$result)

$result[0] will output src="media/projectx/agent/author/post/2/image/publisher.PNG"

answered Sep 15, 2016 at 13:01

iKev61

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