java.lang.ClassCastException: java.lang.Long cannot be cast to java.lang.Integer in java 1.6

Question

Even I'm casting Object into int, but this exception occur...

Actually my Hibernate-JPA method was return Object then I'm converting that Object into int...

Here is my Hibernate code:

@Transactional
public Object getAttendanceList(User user){

    Query query = entityManager.createQuery("select Count(ad) from AttendanceDemo ad inner join ad.attendee at  where at.user=:user",
            Long.class);
    query.setParameter("user", user);
    return query.getSingleResult();
}

Now I'm converting this Object as int:

int k = (Integer) userService.getAttendanceList(currentUser);

I'm converting Object to Integer.

Looks like getAttendanceList is returning you Long. Can you post the code for the same — ajay.patel
– ajay.patel, Commented Jun 18, 2013 at 8:29
Are you sure you're returning an Integer? ClassCastException says that you're not returning an Integer... — Matteo N.
– Matteo N., Commented Jun 18, 2013 at 8:31
Yes.. i want to store getAttendanceList() method return value into k. then only ClassCastException coming and now i'm casting to (Integer) but again that exception come.. — SWEE
– SWEE, Commented Jun 18, 2013 at 8:34

fge · Accepted Answer · 2013-06-18 08:28:44Z

74

Use:

((Long) userService.getAttendanceList(currentUser)).intValue();

instead.

The .intValue() method is defined in class Number, which Long extends.

answered Jun 18, 2013 at 8:28

fge

122k35 gold badges266 silver badges340 bronze badges

Sign up to request clarification or add additional context in comments.

6 Comments

SWEE Over a year ago

But IDE shows... The method intValue() is undefined for the type Object

johnchen902 Over a year ago

Why not use ((Number) userService.getAttendanceList(currentUser)).intValue();

fge Over a year ago

@johnchen902 yes, that is true... But in this case I am not sure OP really wants that. Or that the db model will change from Long to some other numeric type overnight ;)

SWEE Over a year ago

oh... thankyou.. fge.. it's working... but when we write like ((Number) userService.getAttendanceList(currentUser)).intValue(); it is not working why???

fge Over a year ago

@user2496295 uh! That should work... Or do you have another Number class which is not the JDK's?

|

Jeroen Kransen · Accepted Answer · 2013-06-18 08:41:24Z

6

The number of results can (theoretically) be greater than the range of an integer. I would refactor the code and work with the returned long value instead.

answered Jun 18, 2013 at 8:41

Jeroen Kransen

1,5013 gold badges22 silver badges48 bronze badges

Comments

Yehouda · Accepted Answer · 2022-05-18 10:44:52Z

0

You can do like that :

int k = Math.toIntExact((Long) userService.getAttendanceList(currentUser));

answered May 18, 2022 at 10:44

Yehouda

1221 silver badge6 bronze badges

Comments

Mr Etineh · Accepted Answer · 2023-05-31 18:00:36Z

0

Just change the long to Number Remember your database is Number not int or long.

answered May 31, 2023 at 18:00

Mr Etineh

11 bronze badge

Collectives™ on Stack Overflow

java.lang.ClassCastException: java.lang.Long cannot be cast to java.lang.Integer in java 1.6

4 Answers 4

6 Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

6 Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related