How can I create a new array that contains all elements numbered nth to (n+k)th from an old array?
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5 Answers
You want the slice method.
var newArray = oldArray.slice(n, n+k);
1 Comment
Quentin
While W3Schools doesn't appear to have any errors on that page (which is unusual), I think the MDC documentation is better: developer.mozilla.org/en/Core_JavaScript_1.5_Reference/…
i think the slice method will do what you want.
arrayObject.slice(start,end)
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Slice creates shallow copy, so it doesn't create an exact copy. For example, consider the following:
var foo = [[1], [2], [3]];
var bar = foo.slice(1, 3);
console.log(bar); // = [[2], [3]]
bar[0][0] = 4;
console.log(foo); // [[1], [4], [3]]
console.log(bar); // [[4], [3]]
Comments
Prototype Solution:
Array.prototype.take = function (count) {
return this.slice(0, count);
}
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lets say we have an array of six objects, and we want to get first three objects.
Solution :
var arr = [{num:1}, {num:2}, {num:3}, {num:4}, {num:5}, {num:6}];
arr.slice(0, 3); //will return first three elements
answered Dec 14, 2016 at 20:59
Malik Khalil Ahmad
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