why *.jsp url pattern in web.xml does not work

Question

I wanna map all request to the TestHandler Servlet, so I use /* pattern.
Then I wanna exclude jsp mappings, so I add *.jsp pattern mapping to jsp in front of /*.
Problem: .jsp doesn't catch the url http://localhost/project/fun.jsp at all. In stead, / pattern catches it. Why? How can this happen ?

<servlet-mapping>
  <servlet-name>jsp</servlet-name>
  <url-pattern>*.jsp</url-pattern>
</servlet-mapping>

<servlet-mapping>
  <servlet-name>TestHandler</servlet-name>
  <url-pattern>/*</url-pattern>
</servlet-mapping>

But if I use a certain url-pattern like fun.jsp instead of *.jsp, it works. The fun.jsp pattern catch the url above. Who can tell me why ?

Balint Bako · Accepted Answer · 2013-06-19 10:01:47Z

2

The patterns ending with /* (path rules) are matched before the *. starting (extension rules) mappings. The exact URI is an exact match, which is the 1st in the evaluation order.

Set TestHandler as default servlet, that should work.

<servlet-mapping>
  <servlet-name>TestHandler</servlet-name>
  <url-pattern>/</url-pattern>
</servlet-mapping>

edited Jun 19, 2013 at 10:01

answered Jun 19, 2013 at 9:37

Balint Bako

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5 Comments

gaoshougaoshou Over a year ago

so, How can I change the order?

Balint Bako Over a year ago

you can't, this is the servlet specification

Balint Bako Over a year ago

You should try using / (and not /*) as url-pattern, which is the default servlet

gaoshougaoshou Over a year ago

Looks like / works very well. Thank you very much! But I don't understand the difference between / and /*! And where can find the documentation of this part (the url-pattern) ?

Balint Bako Over a year ago

/ is THE default mapping, which is different from the /* ending mappings! This page explains it quite well: javapapers.com/servlet/what-is-servlet-mapping For the exact specification you have to check the Java Servlet specification I'm afraid...

Pavan · Accepted Answer · 2013-06-19 09:18:42Z

1

To write a servlet mapping there should a servlet class defined.

<servlet>
    <servlet-name>TestHandler</servlet-name>
    <servlet-class>FULLY QUALIFIED NAME OF THE CLASS</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>TestHandler</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

Please note :::: TestHandler is the servlet name and this servlet is mapped to url in the JSP (view) (url pattern /*)

Similarily for another servlet I am adding the servlet class

 <servlet>
    <servlet-name>jsp</servlet-name>
    <servlet-class>FULLY QUALIFIED NAME OF THE CLASS</servlet-class>
  </servlet>

 <servlet-mapping>
   <servlet-name>jsp</servlet-name>
   <url-pattern>*.jsp</url-pattern>
 </servlet-mapping>

This all lines of code should be written in web.xml

answered Jun 19, 2013 at 9:18

Pavan

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1 Comment

gaoshougaoshou Over a year ago

Thank you! I know what you mean. I have the <servlet-class> part. But actually, jsp is a servlet defined in Tomcat/conf/web.xml.

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