Java class implementing a method with a parameter that is of the subtype specified in the interface

Question

I am having some trouble grasping generics. I've read through Oracle's tutorial on generics and it doesn't seem to address my question. I also don't know what to search for in finding my answer.

Let's say that I have the following code:

public abstract class Buff<V> {
    public V value;
{

public interface Buffable<V> {
    public void buff(Buff<V extends Buff> buff);
}

public class DoubleBuff extends Buff<double> {
    public double value;
}

public class DoubleBuffable implements Buffable<DoubleBuff> {
    public void Buff(DoubleBuff buff) {
        //implementation
    }
}

I want to be able to create classes that inherit Buff and have the member "value," but specify value's type (See DoubleBuff). I also want to define classes that implement the buff method using an input parameter that is of a subtype of Buff.

DoubleBuffable is some class that implements Buffable, but expects an input of DoubleBuff and not StringBuff.

Am I expressing my generics correctly?

acdcjunior · Accepted Answer · 2013-06-19 14:30:52Z

Firstly, syntax. The declaration:

public interface Buffable<V> {
    public void buff(Buff<V extends Buff> buff);
}

Should be:

public interface Buffable<V extends Buff> {
    public void buff(Buff<V> buff);
}

The type variable you want, should be specified in the class declaration.

But you say:

I also want to define classes that implement the buff method using an input parameter that is of a subtype of Buff.

This way, the below declaration would suit your statement better:

public interface Buffable<V extends Buff<?>> {
    public void buff(V buff);
}

You may want to change that <?> part if you need a more specific type of Buff.

Lastly, other required change and the final classes:

public abstract class Buff<V> {
    public V value;
}
public interface Buffable<V extends Buff<?>> {
    public void buff(V buff);
}
// instead of primitive types, you should use their wrappers: double-->Double
public class DoubleBuff extends Buff<Double> {
    public double value;
}
public class DoubleBuffable implements Buffable<DoubleBuff> {
    public void buff(DoubleBuff buff) {
        //implementation
    }
}

ssindelar · Accepted Answer · 2013-06-19 14:31:13Z

2

Primitives can't be used as generic types. Try "Double" instead of "double".

answered Jun 19, 2013 at 14:31

ssindelar

2,8441 gold badge19 silver badges36 bronze badges

Collectives™ on Stack Overflow

Java class implementing a method with a parameter that is of the subtype specified in the interface

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related