bash grep array and output array separately

Question

I'm trying to grep from a given array in a file. I need the count of the array unit and I'm hoping to get the output count per unit, eg: U10 => 2 etc. but when I add more than one unit into the array it seems grep sums up and outputs a single combined count.

Here is my code so far, any help or direction on where to search or where to start would be helpful.

 #!/bin/bash
 echo "Enter file to check:"
 read file
 args=("U10" "U12" "U14")
 pat=$(echo ${args[@]}|tr " " "|")
 grep detected /public/files/$file | grep -Ec "$pat"

devnull · Accepted Answer · 2013-06-20 09:23:19Z

2

You're specifying a regex (U10|U12|U14) to grep and seeking for the count. This is why you're observing that you're getting the sum of the count of individual matches.

Specify one pattern at a time:

#!/bin/bash
echo "Enter file to check:"
read file
args=("U10" "U12" "U14")
for pat in ${args[@]}; do
  echo -ne "${pat}\t" ; grep detected /public/files/$file | grep -c "$pat"
done

You probably don't need to pass -E to grep.

answered Jun 20, 2013 at 9:23

devnull

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1 Comment

kirchner20 Over a year ago

Thanks devnull, it works as I wanted it to work! Thanks Again!

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