I want to ensure that all resources are being cleaned correctly. Is this a safe thing to do:
try:
closing(open(okFilePath, "w"))
except Exception, exception:
logger.error(exception)
raise
EDIT:
Infact, thinking about it, do I even need the try/catch as I am raising the exception anyways I can log at a higher level. If it errors on creating the file, one can assume there is nothing to close?
To be sure that the file is closed in any case, you can use the with statement. For example:
try:
with open(path_to_file, "w+") as f:
# Do whatever with f
except:
# log exception
as f part out.# Do whatever with f line to just pass or put everything on one line with open(path_to_file, w+): pass.
with ...: pass is oneliner). You can do open(path_to_file, "w+").close() which opens (creates if not present) and then closes the file.
you can use this to just create a file and close it in one line.
with open(file_path, 'w') as document: pass
The simplest solution would be:
open(fileName, 'w').close()
The mknod function creates a new file without opening it
import os
import stat
os.mknod('test', 0o600 | stat.S_IFREG)
# 0o600 -> owner can read+write file, group and other have no permissions
# stat.S_IFREG -> create regular file, instead of character/block device, pipe, or other special file
Caveat: only available on Unix
If you want a real one liner:
os.remove("echo > YourFile")
It will work on Linux and Windows.
open(okFilePath, 'w+').close()?openraises an exception, it won't be closed.with open(path, 'w+'): passcan technically be expressed on a single line though, and that will handle exceptions.'x'mode for creating a file or failing if it exists already/cannot be created.