Java RegEx Trouble: Matching Function Body

Question

having quite some trouble with the following regex.

String fktRegex ="public double " + a+ "2" + b + "(double value) {return value * (.*);}\n";

a and b are Strings that are inserted individually.

The regex works just fine until I want to identify also the number with it. That's the (.*) part... Any help`? Would be really glad! Thanks.

C.

Can you provide an example of the text you are searching in and a copy of the compiled regular expression please? — Adam
– Adam, Commented Jun 23, 2013 at 14:17
public double abc2xyz(double value) {return value * 100000;} However the datetype could be any numberbased datatype The text is a java sourcefile obviously. Don't know what u mean with compiled regex? — Chaoz77
– Chaoz77, Commented Jun 23, 2013 at 14:31

Pshemo · Accepted Answer · 2013-06-23 14:49:12Z

2

Judging by your example I think you need to escape few regex meta-characters like { } ( ) * so your regex should probably look more like

"public double " + a + "2" + b + "\\(double value\\) \\{return value \\* (.*);\\}\n";

Demo

// abc2xyz
String a = "abc";
String b = "xyz";

String fktRegex = "public double " + a + "2" + b + "\\(double value\\) \\{return value \\* (.*);\\}\n";

String data = "public double abc2xyz(double value) {return value * 100000;}\n";
Pattern p = Pattern.compile(fktRegex);
Matcher m = p.matcher(data);

if(m.find()){
    System.out.println(m.group(1));
}else{
    System.out.println("no match found");
}

edited Jun 23, 2013 at 14:49

answered Jun 23, 2013 at 14:40

Pshemo

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4 Comments

Chaoz77 Over a year ago

Cool, thanks!!! The only thing is now, that I the number back but I was planning to replace the whole function...?

Pshemo Over a year ago

@Chaoz77 I am not sure what you are trying to say (maybe its because my English is not too good yet). Try to describe it more or maybe even create another/separate question.

Chaoz77 Over a year ago

Sorry... Typo due to lacking browser... I was asking if there's a way to replace the whole function? The way u described it, i get back only the number. I don't want to extract the factor but the whole function and replace it with my regex.

Pshemo Over a year ago

@Chaoz77 if you want to get entire match then instead of group(1) use group(0) or just group(). Group 1 is the part between first parenthesis so part in regex so (.*) that is after return value \\* . If you would like want to lets say find entire return then you should probably use something like \\{(return value \\*.*;)\\} and now group 1.

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