Passing an array in PHP to another PHP script through html hidden form element

Question

My question is that when I copy my array elements between different php scripts using session variables, nothing gets printed out. The following are my two php files.

file1.php

   $SQL = "SELECT * FROM tblquestions";
if ($db_found) {
        $result = mysql_query($SQL);
        $numRows = mysql_num_rows($result); //return number of rows in the table
        echo '<FORM NAME ="form1" METHOD ="POST" ACTION ="file2.php">';
        for ($i = 1; $i <= 2; $i++)
        {
            $db_field = mysql_fetch_assoc($result);
            $qID[$i] = $db_field['QID'];
            $question[$i] = $db_field['Question'];
            $A[$i] = $db_field['qA'];
            $B[$i] = $db_field['qB'];
            $C[$i] = $db_field['qC'];
            echo '<P>';
            print $question[$i];
            echo '<P>';
            echo "<INPUT TYPE = 'Radio' Name = '".$qNum."'  value= 'A'>"; 
            print $A[$i];
            echo '<P>';
            echo  "<INPUT TYPE = 'Radio' Name = '".$qNum."'   value= 'B'>"; 
            print $B[$i];
            echo '<P>';
            echo  "<INPUT TYPE = 'Radio' Name = '".$qNum."'   value= 'C'>"; 
            print $C[$i];
            //if (isset($_POST[$name_Value]))
            $survey_Answers[$i-1] = $_POST[$qNum];
            print '</BR>'.$survey_Answers[$i-1]."</BR>";
            $question_Number = ltrim($qNum,'q');
            $question_Number++;
            $qNum ='q'.$question_Number;
        }

        echo '<p>';
    session_start();
    $_SESSION['answers'] = $survey_Answers;
        echo '<INPUT TYPE = "Submit" Name = "Submit1"  VALUE = "Click here to vote">';

        echo '</form>';

On my Second file (file2.php), I have the following:

<?PHP
session_start();
if (isset($_POST['Submit1'])) {
        $results = $_SESSION['answers'];
        print $results[0];
?>

Nothing gets printed out when executing the above code.

Thanks in advance

Why aren't you simply saving that to a session variable? Anything in HTML document can be manually modified. — N.B.
– N.B., Commented Jun 24, 2013 at 14:23
Not sure if it's a typo in the question, but you're missing an = after value — billyonecan
– billyonecan, Commented Jun 24, 2013 at 14:24
When for the first time you submit the form, //if (isset($_POST[$name_Value])) $survey_Answers[$i-1] = $_POST[$qNum]; print '</BR>'.$survey_Answers[$i-1]."</BR>"; $question_Number = ltrim($qNum,'q'); $question_Number++; $qNum ='q'.$question_Number; this part works for the first time. so the next time you submit the form, you'll get value for $Survey_answers not on the first time. You can simply work with the radio input, instead of relying another array. — Fallen
– Fallen, Commented Jun 24, 2013 at 14:52
do you mean adding a hidden form element in my first for loop. Again, don't I need an array to hold these multiple values as I'm going to use them on another php script. — Ahmed Ebaid
– Ahmed Ebaid, Commented Jun 24, 2013 at 14:56

Drew · Accepted Answer · 2013-06-24 18:04:36Z

1

I am pretty sure that the session values stored need to be strings.

In file1.php change:

$_SESSION['answers'] = $survey_Answers;

to this:

$_SESSION['answers'] = json_encode($survey_Answers);

Then in file2.php change:

$results = $_SESSION['answers'];

to this:

$results = json_decode($_SESSION['answers']);

answered Jun 24, 2013 at 18:04

Drew

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14 Comments

Ahmed Ebaid Over a year ago

I tried this. However, I modified my action to file1.php. So I typed the following command: echo $_SESSION['answers'][0]; and the output was a square bracket.

Drew Over a year ago

In file1 just after: $_SESSION['answers'] = json_encode($survey_Answers); add this line and post the results: echo var_dump($_SESSION['answers']);

Ahmed Ebaid Over a year ago

actually, what is making me crazy is that when I use any other variable that is not Array type. Everything works correctly.

Ahmed Ebaid Over a year ago

this is the output of executing the following: echo var_dump($_SESSION['answers']); string '[]' (length=2)

Drew Over a year ago

It looks like the $survey_Answers variable is an empty array. To confirm, can you do a var_dump($survey_Answers); just above the code $_SESSION['answers'] = json_encode($survey_Answers);

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