How to get specific value from array?

Question

I have an array like this:

$Array = array("0","2","0","5","0");

and the specific value I want is 2 and 5, so the array will be like this:

$newArray = array("2","5");

Thanks.

If you have the values already why do you need to retrieve them from the array? — Jim
– Jim, Commented Jun 26, 2013 at 15:11
[2, 5] is not a "specific value." You've filtered elements from your array. This type of operation is called a "Filter", because it removes some elements of the array based on a given rule. In this case, the value must equal 2 or 5. You may want to rephrase your question to something more like "How can I filter this array to retain only certain given values?" — Peaches491
– Peaches491, Commented Jun 26, 2013 at 15:12
I'll go even simpler: $newArray = array($Array[1], $Array[3]); Since we're being vague about the qualifiers. — Brad Christie
– Brad Christie, Commented Jun 26, 2013 at 15:18

Paul · Accepted Answer · 2013-06-26 15:24:03Z

2

Since "0" is falsey you can just use array_filter to remove all the "0" from your array:

$array = array("0","2","0","5","0","7","0");
$newArray = array_filter($array); // newArray is: ["2", "5", "7"]

answered Jun 26, 2013 at 15:24

Paul

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Dave · Accepted Answer · 2013-06-26 15:14:43Z

0

So you basically just want to remove zero's from your array? I think this should work you just pass the function the array and the item you wish to replace (note this code is untested you may need to tweak it a little)

function array_replace($incomingarray, $tofind)
{
    $i = array_search($tofind, $incomingarray);
    if ($i === false) {
        return $incomingarray;
    } else {
        unset($incomingarray[$i]);
        return array_replace($incomingarray, $tofind);
    }
} 

$Array = array("0","2","0","5","0");
$a = array_replace($Array, 0); 
var_dump($a);

answered Jun 26, 2013 at 15:14

Dave

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Comments

Yogesh Suthar · Accepted Answer · 2013-06-26 15:14:54Z

0

You can use array_filter

function fil($var)
{
if($var == 2 || $var == 5)
return($var);
}
$array1 = array(0,2,0,5,0);
print_r(array_filter($array1, "fil"));

Output

 Array
(
[1] => 2
[3] => 5
)

Demo

answered Jun 26, 2013 at 15:14

Yogesh Suthar

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1 Comment

Dave Over a year ago

Nice solution using it as a call back. Could get complex if using a variable match params though surely as he'd have to generate the if clauses on the fly?

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