I'm trying to do something fairly simple, and I'm just coming up short. Here is an example variable I'm trying to work with:
20,80,443,53
The variable is just a string of ports separated by commas. I need to get those into an array.
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5 Answers
Set IFS to , and use the read command with a here-string
IFS=, read -r -a arr <<<"20,80,443,53"
printf "%s\n" "${arr[@]}"
20
80
443
53
Comments
Here is one way:
#!/bin/bash
v="20,80,443,53"
IFS=, a=($v) # Split
echo ${a[0]} # Display
echo ${a[1]}
echo ${a[2]}
echo ${a[3]}
Update
Thanks to gniourf_gniourf for pointing out that IFS was modified as the result of the assignment. Here is my quirky work around. Now I see why others did things differently.
v="20,80,443,53"
PREV_IFS="$IFS" # Save previous IFS
IFS=, a=($v)
IFS="$PREV_IFS" # Restore IFS
echo ${a[0]}
echo ${a[1]}
echo ${a[2]}
echo ${a[3]}
1 Comment
gniourf_gniourf
Caution, this will globally set the
IFS variable! will bite you in the back if you forget about it.var="20,80,442,53"
IFS=, read -ra ary <<< "$var"
printf "%s\n" "${ary[@]}"
20
80
442
53
Comments
Ports=('20','80','443','53');
for e in "${lic4l[@]}"; do
echo $e
I hope this will help and print the ports in the given variable.
2 Comments
gniourf_gniourf
Does this actually answer the question?
user2448541
yes it will add all of your ports into an array which later you can use for display actually it will be Ports=('20','80','443','53'); for e in "${Ports[@]}"; do echo $e
With SED it becomes a one-liner:
a=($(sed 's/,/ /g' <<< "20,80,443,53"))
printf "%s\n" "${a[@]}"
20
80
443
53
