remove space and add comma in python

Question

Here is my code:

import fileinput


input_file = 'in.txt'
output = open('out.txt', 'w+')


for each_line in fileinput.input(input_file):
    output.write(x.strip() for x in each_line.split(','))

I get "expect character buffer" as the error. I am not sure what is the best way to go about this? I am trying to remove all tabs and spaces and replace them with a comma.

edit: forexample my data looks like:

1   2335    mike

1   4089    doug

and I want to turn it into

1,2335,mike noll

1,4089,doug funny

edit, i only want to remove the first 2 spaces in the first 2 columns

x.strip() for x in each_line.split(',') evaluates to a generator (which you can turn into a list by surrounding with []s) but write() does not accept a generator. — Matt Ball
– Matt Ball, Commented Jun 28, 2013 at 20:17

karthikr · Accepted Answer · 2013-06-28 20:16:58Z

1

x.strip() for x in each_line.split(',') does returns a generator object (not a string buffer that is expected by the output.write)

You can do:

with open('out.txt', 'w+') as output:
    for each_line in fileinput.input(input_file):
        output.write("\n".join(x.strip() for x in each_line.split(',')))

answered Jun 28, 2013 at 20:16

karthikr

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1 Comment

oleg Over a year ago

It returns generator object indeed

Ashwini Chaudhary · Accepted Answer · 2013-06-28 20:46:50Z

0

Use str.join to join the list into a string and then write it to the file.

In your code you're actually passing a genexp to file.write.

for each_line in fileinput.input(input_file):
    output.write(" ".join(x.strip() for x in each_line.split(',')) +'\n')

Update:

with open('out.txt', 'w') as f:
    for line in fileinput.input('input.txt'):
        line = line.split(None,2)
        f.write(','.join(line))

edited Jun 28, 2013 at 20:46

answered Jun 28, 2013 at 20:17

Ashwini Chaudhary

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2 Comments

ChairmanMeow Over a year ago

How would I save it into a file? instead of printing it?

Don Over a year ago

open a file x = open('filename','w') then just add a x.write(...) around what is after the print

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