Javascript Loop Delay needed

Question

I Need 3 second delay after 2nd loop. place is commented out. pleaes help.

var x = [[1,2,3,4,5,6,7],[8,9,10,11,12,13,14],[15,16,17,18,19,20,21],[22,23,24,25,26,27,28],[29,30,31,32,33,34,35],[36,37,38,39,40,41,42],[43,44,45,46,47,48,49]];
var j=indx='';
var n = 7;
var slice = j= indx='';
for (slice = 0; slice < 2 * n - 1; ++slice) {
    var z = slice < n ? 0 : slice - n + 1;
    for (j = z; j <= slice - z; ++j) {
        indx = x[j][slice - j]-1;
        console.log(indx);
    }
    //window.setTimeout("", 1000);
    //i need delay here.----------------------
}

shift66 · Accepted Answer · 2013-06-30 10:02:35Z

1

use setInterval(callback, time). It's the same as setTimeout but function will be called forever.
clearInterval should be called with your interval's id to stop execution.
setInterval function returns that id

var intervalId = setInterval(function(){
    var z = slice < n ? 0 : slice - n + 1;
    for (j = z; j <= slice - z; ++j) {
        indx = x[j][slice - j]-1;
        console.log(indx);
    }
    if(++slice >= 2*n-1)
        clearInterval(intervalId);
}, 3000);

answered Jun 30, 2013 at 10:02

shift66

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