I am making an program that simulates the roll of a dice 100 times. Now I want to sort the output of the random numbers that are given by the program. How do I have to do that?
import random
def roll() :
print('The computer will now simulate the roll of a dice 100 times')
list1 = print([random.randint(1,6) for _ in range(100)])
roll()
You do not have a list. The print() function returns None, not whatever it just printed to your terminal or IDE.
Store the random values, then print:
list1 = [random.randint(1,6) for _ in range(100)]
print(list1)
Now you can just sort the list:
list1 = [random.randint(1,6) for _ in range(100)]
list1.sort()
print(list1)
return list1 to return the list from the roll() function.list1.sort() call, it returns None as it sorts the list *in place.The above problem can also be solved using for loop as follows -
>>> import random
>>> mylist = []
>>> for i in range(100):
mylist.append(random.randint(1,6))
>>> print(mylist)
To sort the list, issue the following commands -
>>> sortedlist = []
>>> sortedlist = sorted(mylist)
>>> print(sortedlist)
If you don't need the original list:
list1.sort()
If you need the original list:
list2 = sorted(list1)
See python.org: http://wiki.python.org/moin/HowTo/Sorting/
