jQuery - Ajax success parameter as object function

Question

jQuery - ajax success parameter I want to know how to give a object method (function), on the success parameter, to the ajax function (sorry for my English)

lets say I already set my ajax.setup with all I need to call a PHP on the server.

function myClass(id)
{
  this.id = id;

  this.showValues=function(xml) 
  {
    alert(this.id); // to prove we r in the right object
    alert(typeof(xml)); // to prove we got the xml     
  };

  this.retrieveValues=function()
  { 
    // wont call the method, this is just text, like writing sucess:"hello"
    $.ajax({success: this.id+'.showValues'}); 


   // calls the method but this.id is undefined (xml is received though)
    $.ajax({success: this.showValues}); 


    // wont call the method
    $.ajax({success: new Function(this.id+'.showValues')}); 


    // calls the method with the right id but xml is undefined
    $.ajax({success: new Function(this.id+'.showValues()')}); 


    // js error - "xml not defined"
    $.ajax({success: new Function(this.id+'.showValues(xml)')}); 


    // of course, next line works, but I don't want to define the function here
     $.ajax({success: function() { alert(this.id); alert(typeof(xml)); } });    
     
  };

}


// even declaring the object as global, so the class has a chance to call a method using the var name
// which is this.id+'.retrieveValues' ==> object1.retrieveValues
var object1;

function Main() // main =d
{
  object1 = new myClass('object1');
  object1.retrieveValues();

}

again, sorry for my bad English .. learning still. I hope someone can help me, thank you

dedoz · Accepted Answer · 2009-11-16 05:57:12Z

1

found it using Function api help <_< i was missing the "xml" parameter

$.ajax({success: new Function("xml",this.id+'.showValues(xml)')});

new Function("xml",this.id+'.showValues(xml)') is like saying

function(xml) { object1.showValues(xml); }

thanks dedoz. no problem. =D

answered Nov 16, 2009 at 5:57

dedoz

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