PHP: including 2 same php files in 1 page

Question

i have a code

<div class="b4_content">
    <div class="col_left3 FloatLeft">
        <h3>Clients / Projects</h3>
        <div id="left_menu" class="left_menu">
          <?php
            require("admin/Connection/connection.php");
            require("admin/functions/functions.php");
            $toplvl=0;
            /* 1st include of linkCategory.php */
            include "admin/functions/linkCategory.php";
          ?>
        </div>
    </div>
    <div class="col_right3 FloatRight ">
        <div class="cright_padd">
          <?php
            $uploader="admin/";
            $catID = $_GET['catID'];                    
            if($catID==""){
                $toplvl=2;
                /* 2nd include of linkCategory.php */
                include "admin/functions/linkCategory.php";
            } else {
                $toplvl=0;
                include "admin/functions/viewImages.php";
            }
          ?>
        </div>
    </div>
    <div class="ClearBoth"></div>
</div>

As you can see i have 2 includes (admin/functions/linkCategory.php) with same pages My Problem is, the second include "admin/functions/linkCategory.php" does not show up.

Can you help me out

well i nid the same page. il just need to show level 1 and 2 of the category list. my indicator for that is $toplvl — Treby
– Treby, Commented Nov 16, 2009 at 7:28
Are you sure you are getting inside the conditional block to include it a second time? Try putting an echo "in here" after $toplvl=2; to make sure you are definitely hitting the include — Ian
– Ian, Commented Nov 16, 2009 at 7:29
You don't have any functions, classes, or constants declared in linkCategory.php, do you? If you do... PHP will throw an error and cause your script to halt when it's included for the second time. — brianreavis
– brianreavis, Commented Nov 16, 2009 at 7:39

jason · Accepted Answer · 2009-11-16 08:05:49Z

3

I guess $toplvl is a flag that's used within "admin/functions/linkCategory.php" to do different things. So, maybe the error isn't in this chunk, but in linkCategory.php itself.

edited Nov 16, 2009 at 8:05

jason

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answered Nov 16, 2009 at 7:32

user70568

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2 Comments

Treby Over a year ago

Man your right.. nice guess.. i had a function in linkCategory.php, calling it twice will duplicate the created function. Thanks man. your thought helps.

vyger Over a year ago

That's the reason why I asked you to post linkCategory.php. :-) I gave +1 to Scott!

mpen · Accepted Answer · 2009-11-16 07:26:02Z

2

My guess is that $catID is NOT equal to the empty string.

And btw, bolding doesn't work inside code blocks (if that's what you were trying to do).

answered Nov 16, 2009 at 7:26

mpen

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1 Comment

Treby Over a year ago

It is an empty string. coz i tried echoing inside the condition

outis · Accepted Answer · 2009-11-16 07:44:28Z

0

As an alternative, wrap whatever linkCategory.php outputs in a function. Include linkCategory.php once and replace the includes with a call to the function.

answered Nov 16, 2009 at 7:44

outis

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Comments

Raz · Accepted Answer · 2009-11-16 08:02:34Z

0

if the problem still persists, you could set error reporting to show all and see if there's any output

answered Nov 16, 2009 at 8:02

Raz

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