JQuery .ajax data not defined

Question

I have a $.ajax request, and when i send response data with success:function(data), I get the data but for some reason I can't use it in If Statement:

    $.ajax({
      type: "POST",
      url: "control.php",
      data: {"txtNumFattura" : $("#txtNumFattura").val(),
             "txtDataFattura": $("#txtDataFattura").val()},

      success: function(data) {
        console.log(data);
        if (data == 'OK') {
          console.log("Chiave non ancora utilizzata");
          $("#submitMyForm").removeAttr("disabled");
        } 
        else if(data == 'KO') {
          $("#mySubmitForm").attr("disabled","disabled");
          console.log("Chiave Utilizzata");
        };
      }
    });

For instance console.log gives me "OK" or "KO" but it seems like it doesn't read it in the if Statement.

It just gives in response "OK" if the value inserted is not already used as a Primary Key in my table. — Roomka
– Roomka, Commented Jul 4, 2013 at 20:33

Devin Crossman · Accepted Answer · 2013-07-04 20:14:11Z

1

Try

if(data.toLowerCase().indexOf('ok') != -1){
  // ok was found
} else if (data.toLowerCase().indexOf('ko') != -1) {
  // ko was found
} else {
  // neither was found
}

answered Jul 4, 2013 at 20:14

Devin Crossman

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2 Comments

Roomka Over a year ago

Thank you Devin, It helped! Can you explain me please why it didn't work before?!

Devin Crossman Over a year ago

using indexOf will search the whole string for any occurrence of ok or ko whether there is any whitespace or any other characters.. using toLowerCase() is just to make sure that no matter how you typed it Ok, OK, oK, ok it will find it.

Andy G · Accepted Answer · 2013-07-04 20:09:12Z

0

There might be extra whitespace after the OK or KO. Use

console.log("*" + data + "*");

If there is you could use replace() to remove these. For example,

data = data.replace(/\s/g, "");

\s is a whitespace character and 'g' means globally.

answered Jul 4, 2013 at 20:09

Andy G

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Comments

Learner · Accepted Answer · 2013-07-04 20:14:17Z

0

If you are sure that it gives you OK or KO, you can try this:

if ($.trim(data) === 'OK') {
  console.log("Chiave non ancora utilizzata");
  $("#submitMyForm").removeAttr("disabled");
} else if($.trim(data) === 'KO') {
  $("#mySubmitForm").attr("disabled","disabled");
  console.log("Chiave Utilizzata");
};

answered Jul 4, 2013 at 20:14

Learner

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1 Comment

Roomka Over a year ago

Actually this works too! Don't know why, But for some reason it put an extra whitespace.

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