Comparisons with loop in python

Question

I have a problem:

list = [1,2,3,4,5]
a= 3
if a==[item for item in list]:
    print(sth)

why the program never print? thanks...

DO NOT name your variable as list,it internally stands for the type of List — Harry.Chen
– Harry.Chen, Commented Jul 5, 2013 at 10:08

TerryA · Accepted Answer · 2013-07-05 09:52:39Z

5

You're comparing an integer to a list, which will never return True as they are different types. Note that [item for item in list] is exactly the same as just saying list.

You're probably wondering if 3 is in the list; so you can do:

if a in list:
    print(sth)

Or even:

if any(a == item for item in list):
    print(sth)

(Although you really should just use the first option. I only put the second option in as it looks similar to your example :p)

As a side note, you shouldn't be naming lists list, or dictionaries dict, as they are built-in types already, and you're just overriding them :p.

answered Jul 5, 2013 at 9:52

TerryA

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1 Comment

user2518498 Over a year ago

thanks buddy, im quite stupid now after whole day studying programming. also thank you for replying so fast.

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