Java: removing numeric values from string

Question

I have suceeded with the help of this community in removing numeric values from user input, however, my code below will only retrieve the alpha characters before the numeric that has been removed:

import java.util.Scanner;

public class Assignment2_A {

    public static void main(String[] args) {
        Scanner firstname = new Scanner(System.in);
        String firstname1 = firstname.next();
        firstname1 = firstname1.replaceAll("[^A-Z]","");
        System.out.println(firstname1);
    }
}

For example if user input = S1234am, I am only getting back: S. How do I retrieve the remaining characters in the string?

u need to replace lowercase letters as well

Dennis Kriechel
– Dennis Kriechel

2013-07-07 20:29:13 +00:00
Commented Jul 7, 2013 at 20:29 — Dennis Kriechel
– Dennis Kriechel, Commented Jul 7, 2013 at 20:29

jlordo · Accepted Answer · 2013-07-07 20:28:47Z

67

This will remove all digits:

firstname1 = firstname1.replaceAll("\\d","");

answered Jul 7, 2013 at 20:28

jlordo

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Comments

Vishal K · Accepted Answer · 2013-07-07 20:41:06Z

26

You can use:

firstname1 = firstname1.replaceAll("[0-9]","");

This will remove all numeric values from String firstName1.

    String firstname1 = "S1234am";
    firstname1 = firstname1.replaceAll("[0-9]","");
    System.out.println(firstname1);//Prints Sam

edited Jul 7, 2013 at 20:41

answered Jul 7, 2013 at 20:32

Vishal K

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2 Comments

Milan Kumar Over a year ago

This answer is more relevant to the question as using [^A-Za-z] will also remove white spaces and any other values apart from the numeric values.

shevy Over a year ago

I think this is the best answer. The others above are (some) ok, save the -1, but this one is best, IMO, because it is short, concise, clear, and quite to the point. The range specified 0-9 is also what other languages typically use.

Gian · Accepted Answer · 2013-07-07 20:28:06Z

20

Your regular expression [^A-Z] is currently only configured to preserve upper-case letters. You could try replacing it with [^A-Za-z] to keep the lower-case letters too.

answered Jul 7, 2013 at 20:28

Gian

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2 Comments

Gian Over a year ago

Indeed. If the goal is really to remove all digits, then using \\d would be better, but the way it was currently designed suggested the goal might be to just preserve A-Za-z.

user2558595 Over a year ago

Gian, Thank you for your help. I would give you a thumbs up but apparently I am too new on this site to do so. Thank you for your time!

Jorgesys · Accepted Answer · 2017-09-25 21:49:36Z

7

How to remove numeric values from a string:

to do this it will be enough

str.replaceAll("[^A-Za-z]","");

but what if your string contain characters like:

String str = "stackoverflow elenasys +34668555555 # Пивоварова Пивоварова հայեր հայեր አማሪኮ     አማሪኮ kiểm tra kiểmtra ตรวจสอบ ตรวจสอบ التحقق من التحقق من";

most of the characters will be removed too, so this is a better option:

str = str.replaceAll("[\\d.]", "");

to remove all numeric values and get as result:

stackoverflow elenasys + # Пивоварова Пивоварова հայեր հայեր አማሪኮ     አማሪኮ kiểm tra kiểmtra ตรวจสอบ ตรวจสอบ التحقق من التحقق من

edited Sep 25, 2017 at 21:49

answered Sep 25, 2017 at 21:40

Jorgesys

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Comments

fge · Accepted Answer · 2013-07-07 20:29:10Z

1

Your regex:

[^A-Z]

matches anything which is not an uppercase letter.

Which means any lowercase letter will match too.

You should probably use:

[^A-Za-z]

as a regex instead.

Note also that this will not account for anything other than ASCII. It may, or may not, be what you want.

answered Jul 7, 2013 at 20:29

fge

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Comments

Asan · Accepted Answer · 2019-02-28 17:14:00Z

0

public static void main(String[] args) {
    String address = "34732483dhshdsdhajsa8ejdsdd";
    char[] chars = address.toCharArray();
    String aString = "";

    for (int i = 0; i < chars.length; i++) {
        if (!Character.isDigit(chars[i])) {
            aString =aString + chars[i]; 


        }

    }System.out.println(aString);



}

answered Feb 28, 2019 at 17:14

Asan

1

Comments

Community · Accepted Answer · 2020-04-15 04:45:27Z

-1

/*Remove numbers from given specific string*/
public class NewClass6 {

    public static void main(String[] args){
        String s= "hello647hi74joke";
        char[] ch= s.toCharArray();
        System.out.println("Result = " + getString(ch));
    }

    static String getString(char[] ch){
        int m = 0;
        char[] chr = new char[50];
        char[] k = {'0','1','2','3','4','5','6','7','8','9'};

        for(int i = 0; i < ch.length; i++){
           for(int j = 0; j < k.length; j++){  
               if(ch[i]==k[j]){
                   m--;
                   break;
               }
               else {
                   chr[m]=ch[i];
               }
            }
            m++;
         }

         String st = String.valueOf(chr);
         return st;
     }
}

edited Apr 15, 2020 at 4:45

CommunityBot

11 silver badge

answered Mar 15, 2018 at 13:45

Nitish Kumar

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1 Comment

NOhs Over a year ago

Thank you for this code snippet, which might provide some limited, immediate help. A proper explanation would greatly improve its long-term value by showing why this is a good solution to the problem and would make it more useful to future readers with other, similar questions. Please edit your answer to add some explanation, including the assumptions you’ve made.

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