check_output error in python

Question

I am gettin a error while running the below code.

#!/usr/bin/python
import subprocess
import os
def check_output(*popenargs, **kwargs):
    process = subprocess.Popen(stdout=subprocess.PIPE, *popenargs, **kwargs)
    output, unused_err = process.communicate()
    retcode = process.poll()
    if retcode:
        cmd = kwargs.get("args")
        if cmd is None:
            cmd = popenargs[0]
        error = subprocess.CalledProcessError(retcode, cmd)
        error.output = output
        raise error
    return output

location = "%s/folder"%(os.environ["Home"])
subprocess.check_output(['./MyFile'])

Error

subprocess.check_output(['./MyFile'])
AttributeError: 'module' object has no attribute 'check_output'

I am working on Python 2.6.4 .

Do you mean to use the check_output method that's defined? — Travis DePrato
– Travis DePrato, Commented Jul 9, 2013 at 4:38
There's a very nice way to do this, including detecting if it's necessary, given in this answer. — Mike
– Mike, Commented Feb 17, 2015 at 22:50

Just M · Accepted Answer · 2017-02-03 06:01:22Z

7

You probably just want to use check_output, but, just so you know, there is a method subprocess.check_output, but it's not defined until Python 2.7 (http://docs.python.org/3/library/subprocess.html#subprocess.check_output)

You might even want this, which defines the function in the module if it's not there (i.e. running before v2.7).

try: subprocess.check_output
except: subprocess.check_output = check_output
subprocess.check_output()

edited Feb 3, 2017 at 6:01

Just M

28k6 gold badges85 silver badges75 bronze badges

answered Jul 9, 2013 at 4:39

Travis DePrato

4124 silver badges9 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Mike Over a year ago

A nicer way to do that is given in this answer.

Ashwini Chaudhary · Accepted Answer · 2014-08-07 09:06:24Z

6

Just use :

check_output(['./MyFile'])

You've defined your own function, it's not an attribute of subprocess module(for Python 2.6 and earlier).

You can also assign the function to the imported module object(but that's not necessary):

subprocess.check_output = check_output
location = "%s/folder" % (os.environ["Home"])
subprocess.check_output(['./MyFile'])

edited Aug 7, 2014 at 9:06

answered Jul 9, 2013 at 4:37

Ashwini Chaudhary

252k60 gold badges478 silver badges519 bronze badges

3 Comments

misguided Over a year ago

File "DailyCheck.py", line 19, in <module>     check_output(['./MyFile'])   File "DailyCheck.py", line 5, in check_output     process = subprocess.Popen(stdout=subprocess.PIPE, *popenargs, **kwargs)   File "/usr/lib/python2.6/subprocess.py", line 621, in __init__     errread, errwrite)   File "/usr/lib/python2.6/subprocess.py", line 1126, in _execute_child     raise child_exception OSError: [Errno 2] No such file or directory

NOt sure why I am getting this error. The file is definitelythere in the folder specified.

Travis DePrato Over a year ago

Try checking the value of os.getcwd() is correct (should be the directory that MyFile is in).

misguided Over a year ago

@TravisGD you are correct. I had deleted os.chdir(location) by mistake , hence was getting the error.

E.Zolduoarrati · Accepted Answer · 2019-12-10 05:56:22Z

0

try the following:

from subprocess import check_output 
print(check_output(["dir", "C:\\Downloads\\file.csv"],shell=True).decode("utf8"))

ensure that you have \ in your path rather than '/' and "dir" rather "ls"

answered Dec 10, 2019 at 5:56

E.Zolduoarrati

1,6492 gold badges11 silver badges9 bronze badges

Collectives™ on Stack Overflow

check_output error in python

3 Answers 3

1 Comment

3 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

1 Comment

3 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related