I have currently some URL like this :
?param=value&offset=19&size=100
Or like that :
?offset=45&size=50¶m=lol
And I would like to remove for each case the "offset" and the "value". I'm using the regex method but I don't understand how it's really working... Can you please help me for that? I also want to get both values of the offset and the size.
Here is my work...
\(?|&)offset=([0-9])[*]&size=([0-9])[*]\
But it doesn't works at all!
Thanks.
Assuming is Javascript & you only want to remove offset param:
str.replace(\offset=[0-9]*&?\,"")
For Java:
str=str.replaceAll("offset=[0-9]*&?","");
//to remove & and ? at the end in some cases
if (str.endsWith("?") || str.endsWith("&"))
str=str.substring(0,str.length()-1);
With out regex .
String queryString ="param=value&offset=19&size=100";
String[] splitters = queryString.split("&");
for (String str : splitters) {
if (str.startsWith("offset")) {
String offset = str.substring(str.indexOf('=') + 1);//like wise size also
System.out.println(offset); //prints 19
}
}
If you need to use a regular expression for this then try this string in java for the regular expression (replace with nothing):
"(?>(?<=\\?)|&)(?>value|offset)=.*?(?>(?=&)|$)"
It will remove any parameter in your URL that has the name 'offset' or 'value'. It will also conserve any required parameter tokens for other parameters in the URL.
