convert an input value in array

Question

I have this data in an input: [16,57.35], [23,56.26], [34,54.57]

and I want to turn it into an array

var data =$('#data').val();
var array = JSON.parse ("["+data+"]");

I'm having this error

Uncaught SyntaxError: Unexpected token.

How I can fix it or I can convert the input value in array?

Please do a console.log(data) and post here what you are actually passing in. — Bergi
– Bergi, Commented Jul 9, 2013 at 17:13
Also check data.length, maybe there are some non-printing characters in it. — Teemu
– Teemu, Commented Jul 9, 2013 at 17:14

Adil · Accepted Answer · 2013-07-09 17:11:29Z

5

Your code is working check it here, you may need to include required jQuery library or check some thing else in the code causing it.

data = $('#txt1').val();
arr = JSON.parse ("["+data+"]");
console.log(arr);

answered Jul 9, 2013 at 17:11

Adil

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Comments

James Johnson · Accepted Answer · 2013-07-09 17:00:41Z

1

Try using the eval function:

var data = "123, 456, 789";
var array = eval("[" + data + "]");

You'll need to make sure that whatever you're inputting is valid JSON, but the above code will output an array for you. Hope it helps.

answered Jul 9, 2013 at 17:00

James Johnson

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11 Comments

user229044 Over a year ago

It actually is valid JSON, if he's wrapping it in [], which I missed the first time around.

colestrode Over a year ago

be careful, eval is considered harmful: stackoverflow.com/questions/86513/…

James Johnson Over a year ago

@MarcelSoleraAyala: You're welcome. Please make sure to mark the answer if you're satisfied.

Karl Anderson Over a year ago

@meagar - I put the data in at JSONLint and it did not validate. Is there a less rigid interpretation of valid JSON that you are using?

user229044 Over a year ago

@JamesJohnson Regardless, you should be downvoted if you propose a solution that introduces security problems. Downvoting for security concerns is completely valid, whether or not they were explicitly mentioned in the question. However, in this case, such concerns are misguided and unfounded... That said, there is no reason to use eval, when the string is valid JSON. There is some other problem the question's author is ignoring by switch to eval.

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