PHP - mixed strings and variables with addition on the var?

Question

What am I doning wrong in my formatting for these 2 bits of code?

How can I format the mixture of strings and vars to give me the proper output?

$inbody = 60;
$body = "Welcome. For about " . $inbody . "-" . $inbody+15 . " minutes, you'll receive SMS messages." ;

Am I allowed to do inline addition like that? or is my only solution to just declare another variable and put it in? like:

$addedinbody = $inbody + 15 ;

Here is another example IM having trouble with (specifically setting the $body variable):

for ($i=0; $i<=$duration; $i++){
$body = $i+1 . "/" . $duration+1 . " " . $task[$newtask];
}

Code Lღver · Accepted Answer · 2013-07-10 10:24:40Z

1

You need to put the addition in the bracket to tell that there is addition.

Like it:

$body = "Welcome. For about " . $inbody . "-" . ($inbody+15) . " minutes, you'll receive SMS messages." ;

And you problem will be solved.

answered Jul 10, 2013 at 10:24

Code Lღver

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Comments

TMH · Accepted Answer · 2013-07-10 10:51:16Z

0

Like Broken Heart said you need () around the $inbody+15.

Also another tip you dont need to escape out of double quote to insert a variable into a string, but you do in a single quote string.

$body = "Welcome. For about $inbody -" . $inbody+15 . " minutes, you'll receive SMS messages." ;

Same as Broken Heart said applies to your for loop.

for ($i=0; $i<=$duration; $i++){ $body = ($i+1) . "/" . ($duration+1) . " " . $task[$newtask]; }

answered Jul 10, 2013 at 10:51

TMH

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