Given the following string:
var myString = "s1a174o10";
I would like to have the following result:
var s = 1;
var a = 174;
var o = 10;
Each letter on the string matches the following number.
Keep in mind that the string is not static, here is another example:
var myString = "s1p5a100";
You could use a regular expression:
var ITEM = /([a-z])(\d+)/g;
Then put each match into an object:
var result = {};
var match;
while(match = ITEM.exec(myString)) {
result[match[1]] = +match[2];
}
Now you can use result.s, result.a, and result.o.
You can do this with regex:
var vars = {};
myString.replace(/(\D+)(\d+)/g, function(_,k,v){ vars[k] = +v });
console.log(vars); //=> {s: 1, a: 174, o: 10}
replace for something that is not a replace? That falls into the too nasty of a hack for me....
replace for looping matches is common practice in my book... I find the while(assignment) pattern harder to read TBH.replace ejohn.org/blog/search-and-dont-replacegmatch helper using this technique and you're golden. I put a lil' demo here: jsbin.com/iredog/1/editRegex can help you...
var myString = "s1a174o10";
var matches = myString.match(/([a-zA-Z]+)|(\d+)/g) || [];
for(var i = 0; i < matches.length; i+=2){
window[matches[i]] = matches[i+1];
}
WARNING: s,a,o will be global here. If you want, you can declare an object instead of using window here.
