I have a string of in Python
str1 = 'abc(1),bcd(xxx),ddd(dfk dsaf)'
How to use re to parse it into an object say 'results' so I can do something like:
for k,v in results:
print('key = %r, value = %r', (k, v))
Thanks.
4 Answers
Something like this, using re.findall:
>>> str1 = 'abc(1),bcd(xxx),ddd(dfk dsaf)'
>>> results = re.findall(r'(\w+)\(([^)]+)\),?',str1)
for k,v in results:
print('key = %r, value = %r' % (k, v))
...
key = 'abc', value = '1'
key = 'bcd', value = 'xxx'
key = 'ddd', value = 'dfk dsaf'
Pass it to dict() if you want a dict:
>>> dict(results)
{'bcd': 'xxx', 'abc': '1', 'ddd': 'dfk dsaf'}
answered Jul 12, 2013 at 1:19
Ashwini Chaudhary
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Comments
You can also use finditer:
>>> p = re.compile(r'(\w+)\((.*?)\)')
>>> {x.group(1):x.group(2) for x in p.finditer(str1)}
{'bcd': 'xxx', 'abc': '1', 'ddd': 'dfk dsaf'}
>>>
Comments
you could, at a pinch, do it without resorting to regex
str1 = 'abc(1),bcd(xxx),ddd(dfk dsaf)'
results = [x.split('(') for x in str1.split(',')]
results = [(x, y.rstrip(')')) for x, y in results]
print results
[('abc', '1'), ('bcd', 'xxx'), ('ddd', 'dfk dsaf')]
Comments
str1 = 'abc(1),bcd(xxx),ddd(dfk dsaf)'
import re
d = dict(re.findall('(\w+)\((.*?)\)', str1))
# {'bcd': 'xxx', 'abc': '1', 'ddd': 'dfk dsaf'}
for k,v in d.iteritems():
# do whatever
key=abc value=1?