accessing xml stored in xslt variable

Question

This code is not giving desired result.Please help. This code is not giving desired result.Please help. This code is not giving desired result.Please help.

 <xsl:template match="/">
<xsl:variable name="Resp">
    <Response>
        <Status>
            <A></A>
        </Status>
        <RespRec>
            <Data>
                <A1>gmailcom</A1>
                <B1>YES</B1>
                <C1>PRIVACY</C1>
                <D1>00</D1>
            </Data>
            <Data>
                <A1>Ymailcom</A1>
                <B1>DES</B1>
                <C1>TYPE</C1>
                <D1>01</D1>
            </Data>
        </RespRec>
    </Response>
</xsl:variable>
<xsl:element name="Response">

    <xsl:for-each select="$Resp/Response/RespRec/Data">
        <ABCD> <!-- It can repeat as many as Data element is there -->
            <A1>
                <xsl:value-of select="$Resp/Response/RespRec/Data/A1" />
            </A1>
            <B1>
                <xsl:value-of select="$Resp/Response/RespRec/Data/B1" />
            </B1>
            <C1>
                <xsl:value-of select="$Resp/Response/RespRec/Data/C1" />
            </C1>
            <D1>
                <xsl:value-of select="$Resp/Response/RespRec/Data/D1" />
            </D1>
        </ABCD>
    </xsl:for-each>

</xsl:element>
 </xsl:template>

Desired out put:

 <Response>
  <ABCD>
  <A1>gmailcom</A1>
                        <B1>YES</B1>
                        <C1>PRIVACY</C1>
                        <D1>00</D1>
</ABCD>
<ABCD>
<A1>Ymailcom</A1>
                        <B1>DES</B1>
                        <C1>TYPE</C1>
                        <D1>01</D1>
  </ABCD>
  </Response>

But the above code is not giving desired result.Please help. But the above code is not giving desired result.Please help. But the above code is not giving desired result.Please help.

Martin Honnen · Accepted Answer · 2013-07-12 13:59:55Z

1

Assuming you use an XSLT 2.0 processor you can access the contents of a variable with XPath but you need to use relative expressions inside of your for-each e.g.

<xsl:for-each select="$Resp/Response/RespRec/Data">
        <ABCD> <!-- It can repeat as many as Data element is there -->
            <A1>
                <xsl:value-of select="A1" />
            </A1>

I would however suggest to write a template and to push nodes to the template with apply-templates.

answered Jul 12, 2013 at 13:59

Martin Honnen

169k6 gold badges100 silver badges122 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Shaun McCance · Accepted Answer · 2013-07-12 13:59:44Z

0

In XSLT 1.0, the XML you output like that is what's called a result tree fragment. It's not a node set, so you can't use it in an XPath selection. Basically the only thing you can do with it is copy it to the result document. (XSLT 2.0 fixed this silliness, thankfully.)

However, if your XSLT processor supports the EXSLT extensions, you can use exsl:node-set to convert the result tree fragment to a node set. http://exslt.org/exsl/functions/node-set/index.html

<xsl:for-each select="exsl:node-set($Resp)/Response/RespRec/Data">

Make sure to declare the exsl namespace prefix somewhere, preferably on the xsl:stylesheet element.

xmlns:exsl="http://exslt.org/common"

Also, your xsl:value-of statements don't do what you want them to do. When you're inside the xsl:for-each loop, the context node is a Data node. You're then trying to select again from the top, rather than just selecting the child element. Change them to just look like this:

<A1>
  <xsl:value-of select="A1" />
</A1>

answered Jul 12, 2013 at 13:59

Shaun McCance

4843 silver badges4 bronze badges

1 Comment

sasPrasH Over a year ago

How to select child element having same names. Example: <Data><Tag1></Tag1><Tag1></Tag1></Data>. And this nodeset is also stored in a variable.

Collectives™ on Stack Overflow

accessing xml stored in xslt variable

2 Answers 2

Comments

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related