php getting part of a URL into a string

Question

This question is more of a "what is the best/easiest way to do"-type-of-question. I would like to grab just the users id from a string such as

<a href="/profile.php?rdc332738&amp;id=123456&amp;refid=22">User name</a>

I would like to parse the string and get just the "123456" part of it.

I was thinking I could explode the string but then I would get id=123456&blahblahblah and I suppose I would have to somehow dynamically remove the trash from the end. I think this may be possible with regex but I'm fairly new to PHP and so regex is a little above me.

RMcLeod · Accepted Answer · 2009-11-19 09:53:34Z

2

The function parse_str() will help here

$str = "profile.php?rdc332738&amp;id=123456&amp;refid=22";
parse_str($str);
echo $id; //123456
echo $refid; //22

answered Nov 19, 2009 at 9:53

RMcLeod

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2 Comments

Matteo Riva Over a year ago

Seems like parse_str() doesn't handle the (correct) form with & but only understands single &, so this code doesn't work.

Matteo Riva Over a year ago

Also, it just works if the string contains only the query string, if you include profile.php? it gets confused and loses the first argument.

Matteo Riva · Accepted Answer · 2009-11-19 09:52:13Z

1

Just grab any character from id= up to & or " (the latter accounts for the case where id is put last on the query string)

$str = 'a href="/profile.php?rdc332738&amp;id=123456&amp;refid=22">User name</a>';

preg_match('/id=([^&"]+)/', $str, $match);
$id = $match[1];

answered Nov 19, 2009 at 9:52

Matteo Riva

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Comments

Priyank Bolia · Accepted Answer · 2009-11-19 09:48:15Z

0

Regex:

.*id[=]([0-9]*).*$

answered Nov 19, 2009 at 9:48

Priyank Bolia

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Digital Craft Studios · Accepted Answer · 2009-11-19 09:55:10Z

0

if you explode the string:

$string="<a href="/profile.php?rdc332738&amp;id=123456&amp;refid=22">User name</a>"
$string_components=explode('&amp;','$string');

The user id part (id=123456) will be:

$user_id_part=$string_components[1];

then you could do a string replace:

$user_id=str_replace('id=','$user_id_part');

And you have the user id

answered Nov 19, 2009 at 9:55

Digital Craft Studios

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