Numpy array: sequence too large

Question

I have an array of size 11 called 'wavelength' and a larger array of size n called 'MN'. And 'model' is an m by n array.

I'm doing this:

for i in xrange(10+len(wavelength)-2):
  y=np.empty(model[MN][i],float)

and getting this as an error:

  File "test_prog.py", line 658, in <module>
    y=np.empty(model[MN][i],float)
ValueError: sequence too large; must be smaller than 32

I'm not sure what to do about that. I've looked elsewhere online but I can't find anything of obvious substance.

Are you sure you're indexing model correctly? If model is m x n and MN is length n then surely you want model[:,MN]? — ali_m
– ali_m, Commented Jul 16, 2013 at 23:35
sequence too large error means that you are creating a multidimension array that the dimension is large that 32. For example: np.empty([1]*33) will this error. Are you sure you want to create >32 dimension array? If you want to create an empty array the same shape as model[MN][i], you should use: empty_like(). — HYRY
– HYRY, Commented Jul 17, 2013 at 1:22
@HYRY this is the correct answer. Can you please post this as an answer so that people who encounter the same error can easily see it? — elaRosca
– elaRosca, Commented Feb 18, 2014 at 15:34

afinit · Accepted Answer · 2015-05-13 19:43:24Z

27

sequence too large error means that you are creating a multidimension array that has a dimension larger than 32. For example: np.empty([1]*33) will raise this error.

Are you sure you want to create >32 dimension array? If you want to create an empty array the same shape as model[MN][i], you should use: empty_like()

edited May 13, 2015 at 19:43

afinit

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answered Jun 16, 2014 at 4:14

HYRY

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Comments

Hoppo · Accepted Answer · 2020-06-27 00:36:57Z

0

use:

empty_like()

In your case it should be:

y=np.empty_like(model[MN][i],float)

edited Jun 27, 2020 at 0:36

Hoppo

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answered Jun 26, 2020 at 10:39

javed

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