I have a hex String 240300000800000000000000004. I want to add integer in this hex code and get back hex code in java.
As java does not support this muck length of value, so how do we do this?
Thanks Abhishek
5 Answers
String str = "240300000800000000000000004";
BigInteger bi = new BigInteger(str, 16);
Integer ii = 10; // Integer to add
bi = bi.add(new BigInteger(ii.toString()));
System.out.println(bi.toString(16)); // 24030000080000000000000000e
4 Comments
AllTooSir
I didn't downvote , I believe sharing the code triggered the downvote perhaps !
anubhava
@TheNewIdiot: When code is not shared a link is provided then folks complain that better to provide code snippet as links can be broken and now they don't like direct help either.... what to say.
AnaMaria
I believe this should be marked as the answer. As this provides the complete solution instead of a tutorial
Tim Bender
Perhaps the downvoter does not understand what a 'radix' is? Or how one might create an
BigInteger from a hex string by specifying the base 16 to convert from.Use BigInteger in Java
That will satisfy your requirements.
Visit the following tutorial to learn BigInteger in Java : TutorialPoint
Comments
The easiest solution is the already posted one of using BigInteger. However, you can also process the addition in chunks such that the result and any carry will fit in a long. Start at the right hand end with carry-in zero. Take a group of up to 15 hex digits, convert to long, do the addition including any carry-in from the addition to the right of this chunk, store the 15 least significant digits of the result into the output string, and remember the most significant digit to use as the carry-out from this addition, the carry-in to the next addition to the left.
2 Comments
Patricia Shanahan
@TimBender Yes. Replace the 15 byte chunk with a decimal digit, and it's elementary school addition. Replace it with a single bit, and it's the naive way of using a full adder to build a multi-bit adder.
Tim Bender
Yes, and to that end, one could also write a hex adder which will carry a 0-F value up each digit.
BigInteger b = new BigInteger("FF", 16);
BigInteger bPlus1 = b.plus(1);
String hex = bPlus1.toString(16); // 0x100
Comments
BigInteger bigint = new BigInteger("240300000800000000000000004" ,16);
System.out.println(bigint);
BigInteger s = new BigInteger("8");
bigint = bigint.add(s);
System.out.println(bigint);
1 Comment
Surjeet Katwal
Anybody has idea , how to convert a BigInteger into a HexaDeciaml value.
0x