Decoding json string from facebook graph api explorer in php

Question

I am using the graph api to get the profile picture of my facebook app user to a specified width and height.

The url: http://graph.facebook.com/'.$userid.'/picture?width=180&height=220

This will return something in json like { "data": { "url": "https://fbcdn-profile-a.akamaihd.net/hprofile-ak-frc1/c0.0.553.676/s320x320/998591_136374463234627_573810314_n.jpg", "width": 262, "height": 320, "is_silhouette": false } }

I wish to know how to decode that in php and most appropriately how to get the 'url' in the json string returned. Thanks for helping. Note: I'll store the url in a variable in php, then use the url to imagecreatefromjpeg(GD library) and then use the image and merge it with another image.

PHP's decode command is json_decode. Once you've done that, the result is a standard array. From there, you can pick out the url. Use this as a reference: stackoverflow.com/questions/8447084/get-score-from-json-array — DevlshOne
– DevlshOne, Commented Jul 19, 2013 at 10:45

Vladimir Hraban · Accepted Answer · 2013-07-19 11:46:48Z

4

Use json_decode function (http://php.net/manual/en/function.json-decode.php)

It accepts the json string as a parameter and returns either array or an object

$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
$obj = json_decode($json);
$array = json_decode($json, true);

Then, access values like

echo $obj->a;
echo $array['a'];

Both will output

1

In your case you can access the url this way

$obj = json_decode($your_fb_result);
echo $obj->data->url;

OR

$array = json_decode($your_fb_result, true);
echo $array['data']['url'];

Specific to your situation,

$response = file_get_contents('http://graph.facebook.com/'.$userid.'/picture?width=180&height=220&redirect=false');
$array = json_decode($response, true);
echo $array['data']['url'];

See http://php.net/manual/en/function.file-get-contents.php

edited Jul 19, 2013 at 11:46

answered Jul 19, 2013 at 10:45

Vladimir Hraban

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7 Comments

user2599068 Over a year ago

Here is the code: $userprofpicurl='graph.facebook.com/'.$userid.'/…'; $array = json_decode($userprofpicurl, true); echo $array['data']['url']; It doesn't seem to work! :(

Vladimir Hraban Over a year ago

You firstly have to get the output of that URL. file_get_contents will do the trick. See updated answer

Vladimir Hraban Over a year ago

I checked your URL and it returns the image, not the JSON. Check out stackoverflow.com/questions/2070603/… for ways to display binary data as image or just pass the URL in the SRC attribute in IMG tag

Vladimir Hraban Over a year ago

This is the image URL itself. Just try <img src='graph.facebook.com/SOMEUSERID/picture?width=180&height=220'>

user2599068 Over a year ago

what if i use this url instead: graph.facebook.com/100005862221464/…

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