Shared variables between php $_GET and $POST

Question

Why page can not get the $temp_kt value? I tested $_SESSION['temp_kt'] and $_ENV['temp_kt'], neither worked.

<?php
$temp_kt=0;
if(isset($_POST['db']))
{
    if($_POST['db']=="feedback")
    {
        global $temp_kt;
    $temp_kt=$_POST['temp_kt'];
    }
    exit();
}
if(isset($_GET['q']))
{
    echo "temp_kt=".$temp_kt;
}
?>

How could this ever print anything? The code that sets $temp_kt also exits! — Jon
– Jon, Commented Jul 20, 2013 at 10:55

jcubic · Accepted Answer · 2013-07-20 10:59:10Z

3

You have exit in if(isset($_POST['db'])) which mean that you can't have both if statements. If you want to save that value in session you should use code like this:

<?php
session_start();
if (isset($_POST['db'])) {
    if ($_POST['db']=="feedback") {
         $_SESSION['temp_kt'] = $_POST['temp_kt'];
    }
    exit();
}
if (isset($_GET['q'])) {
    echo "temp_kt=" . $_SESSION['temp_kt'];
}
?>

session_start function will enable session for you, you need it at the begining when you set and get session values (it will send cookie to the browser - using header - so you can't have any echo before).

answered Jul 20, 2013 at 10:59

jcubic

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3 Comments

Mr. Alien Over a year ago

Point him out that he needs session_start() at the top else he will post another question in 10 mins saying udefined $_SESSION var

jcubic Over a year ago

@Mr.Alien written info about session_start() function

Mr. Alien Over a year ago

@jcubic yea, better now ;)

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